Simple array loop question Objective-C

Question

1

How can you make this work?

numbers = [[NSMutableArray alloc] initWithObjects: ({int x = 0; while (x <= 60 ) { return x; x++; } })];

Thanks :)

flag	asked Feb 9 at 17:34 Emil 206111 90% accept rate

5

Ha! You a Javascript/Ruby/Scheme/ML programmer by any chance? – quixoto Feb 9 at 17:36

Yep :) Hehe, used to the other ways of doing things, Objective-C is unusual to me.. :P – Emil Feb 9 at 17:49

Dave DeLong · Answer 1 · 2010-02-09 17:37:41Z

5

NSMutableArray * array = [[NSMutableArray alloc] init];

for (int i = 0; i <= 60; ++i) {
  [array addObject:[NSNumber numberWithInt:i]];
}

answered Feb 9 at 17:37

Dave DeLong
21.5k22035

quixoto · Answer 2 · 2010-02-09 17:38:02Z

2

int myStrangeNumberOfItems = 61;

NSMutableArray * numbers = [[NSMutableArray alloc] initWithCapacity: myStrangeNumberOfItems];
for (int i = 0; i < myStrangeNumberOfItems; i++) {
    [numbers addObject:[NSNumber numberWithInt:i]];
}

answered Feb 9 at 17:38

quixoto
3,691919

Off-by-one error. – Matthew Flaschen Feb 9 at 17:38

1

that is totally unacceptable.. it can make a spaceship go nuts – Anurag Feb 9 at 17:40

Fixed. ;) Never loop to <= if you don't need to. – quixoto Feb 9 at 17:41

Cory Kilger · Answer 3 · 2010-02-09 17:39:39Z

First, an NSArray can only hold objects, not primitives. You can add the objects within a for loop like so.

NSMutableAray * numbers = [[NSMutableArray alloc] init];
for (int x = 0; x <= 60; x++)
    [numbers addObject:[NSNumber numberForInt:x]];

Simple array loop question Objective-C

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