std::is_sorted_until

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Defined in header <algorithm>
​template< class ForwardIterator > ForwardIterator is_sorted_until( ForwardIterator first, ForwardIterator last );​	(1)	(C++0x feature)
​template< class ForwardIterator, class Compare > ForwardIterator is_sorted_until( ForwardIterator first, ForwardIterator last,                                  Compare comp );​	(2)	(C++0x feature)

Examines the range [first, last) and finds the largest range beginning at first in which the elements are sorted in ascending order. The first version of the function uses ​operator<​ to compare the elements, the second uses the given comparison function comp.

Contents 1 Parameters 2 Return value 3 Complexity 4 Example 5 See also

Parameters

first, last	-	the range of elements to examine
comp	-	comparison function which returns ​​true​ if the first argument is less than the second. The signature of the comparison function should be equivalent to the following: ​bool cmp(const Type1 &a, const Type2 &b);​ The signature does not need to have ​const &​, but the function must not modify the objects passed to it. The types ​Type1​ and ​Type2​ must be such that an object of type ​ForwardIterator​ can be dereferenced and then implicitly converted to both of them. ​

Return value

The upper bound of the largest range beginning at first in which the elements are sorted in ascending order. That is, the last iterator {{tt|it}] for which range [first, it) is sorted.

Complexity

linear in the distance between first and last

Example

This section is incomplete

See also

is_sorted (C++0x)	checks whether a range is sorted into ascending order (function template)