Use the generic remove algorithm : remove « STL Algorithms Modifying sequence operations « C++

C++
1. Bitset
2. Class
3. Console
4. Data Structure
5. Data Type
6. Deque
7. Development
8. File
9. Function
10. Generic
11. Language
12. List
13. Map Multimap
14. Overload
15. Pointer
16. Queue Stack
17. Set Multiset
18. STL Algorithms Binary search
19. STL Algorithms Heap
20. STL Algorithms Helper
21. STL Algorithms Iterator
22. STL Algorithms Merge
23. STL Algorithms Min Max
24. STL Algorithms Modifying sequence operations
25. STL Algorithms Non modifying sequence operations
26. STL Algorithms Sorting
27. STL Basics
28. String
29. Valarray
30. Vector
Java
Java Tutorial
Java Source Code / Java Documentation
Java Open Source
Jar File Download
Java Articles
Java Products
Java by API
C# / C Sharp
C# / CSharp Tutorial
ASP.Net
JavaScript DHTML
JavaScript Tutorial
JavaScript Reference
HTML / CSS
HTML CSS Reference
C / ANSI-C
C Tutorial
C++ Tutorial
PHP
Python
SQL Server / T-SQL
SQL Server / T-SQL Tutorial
Oracle PL / SQL
Oracle PL/SQL Tutorial
PostgreSQL
SQL / MySQL
MySQL Tutorial
VB.Net
VB.Net Tutorial
Flash / Flex / ActionScript
VBA / Excel / Access / Word
Microsoft Office PowerPoint 2007 Tutorial
Microsoft Office Excel 2007 Tutorial
Microsoft Office Word 2007 Tutorial
C++ » STL Algorithms Modifying sequence operations » removeScreenshots 
Use the generic remove algorithm
 
 
#include <iostream>
#include <cassert>
#include <algorithm>
#include <vector>
using namespace std;

int main()
{
  const int  N = 11;
  int array1[N{12034056708};
  vector<int> vector1;

  for (int i = 0; i < N; ++i)
    vector1.push_back(array1[i]);

  // Remove the zeros from vector1:
  vector<int>::iterator new_end;
  new_end = remove(vector1.begin(), vector1.end()0);

  for (int i = 0; i < (int)vector1.size(); ++i)
    cout << vector1[i];
  cout << "\n\n\n\n\n";
  // The size of vector1 remains the same:
  assert (vector1.size() == N);
  cout << vector1.size();

  cout << "\n\n\n\n\n";

  // The nonzero elements are left in [vector1.begin(), new_end).  Erase the rest:
  vector1.erase(new_end, vector1.end());

  // Show that 3 elements were removed and the nonzero elements remain, in their original order:
  assert (vector1.size() == N - 3);
  cout << vector1.size();
  cout << "\n\n\n\n\n";

  for (int i = 0; i < (int)vector1.size(); ++i)
    cout << vector1[i];

  return 0;
}
/* 
12345678708




11




8




12345678
 */
        
  
Related examples in the same category
1. Use std::remove to delete all element in a vector by value
2. Remove an element and then erase that element
3. Combine remove and erase together
w__ww__._j___a___va__2___s___.__c___o__m | Contact Us
Copyright 2003 - 08 Demo Source and Support. All rights reserved.
All other trademarks are property of their respective owners.