Why does count() return 0 here?

Question

I have the following code :

echo $gibs=Db::getResult($sql,$query);
  print_r($gibs);
  count($gibs);
  if($gibid!='' && count($gibs)<=0){
   $gibs=array(
    'gibid'=>$gibid,
    'userid'=>$userid,
    'isowner'=>false
   );

  }

Resulting output :

ArrayArray ( )

why count($gibs) not returning any thing.

thats why the flow don't going in if condition.

count() returns a value. In your case count($gibs); does nothing. — Linus Kleen
– Linus Kleen, Commented Dec 29, 2010 at 9:26
what is count($gibs) exactly returning? please vardump or print_r it! — Simon
– Simon, Commented Dec 29, 2010 at 9:27
... Maybe because Db::getResult($sql,$query); is returning an empty result set? — cdhowie
– cdhowie, Commented Dec 29, 2010 at 9:27
var_dump(count($gibs));//returns int(0) print_r(count($gibs));//returns 0 — XMen
– XMen, Commented Dec 29, 2010 at 9:31

Silver Light · Accepted Answer · 2010-12-29 09:29:22Z

0

To see the output of count($gibs); you should assign the function to some variable, or print it:

print_r(count($gibs));

In your case, it's value will be 0, because $gibs array is empty (it is seen out of the print_r output).

If condition might not work, because $gibid == 0

answered Dec 29, 2010 at 9:29

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