PHP Problem with array_count_values

Question

I need to get one time occurence on my array, with my code I get only first result here is my example code:

$arr=array("a","a","b","c","d");
$arrs=array_count_values($arr);
for ($i=0; $i<count($arr); $i++)
{
    if($arrs[$arr[$i]]==1)
    {
        //do something...in this example i expect to receive b c and d
    }
}

Thanks in advance

ciao h

Answer 1

$arr=array("a","a","b","c","d");
$arrs=array_count_values($arr);
for ($i=0; $i<count($arr); $i++)
{
    if($arrs[$arr[$i]]==1)
    {
        echo $arr[$i];
    }
}

That should display bcd

Answer 2

$arr=array("a","a","b","c","d");
$result = array();
$doubles = array();
while( !empty( $arr ) ) {
    $value = array_pop( $arr );
    if( !in_array( $value, $arr ) 
            && !in_array( $value, $doubles ) ) {
        $result[] = $value;
    }
    else {
        $doubles[] = $value;
    }
}

Answer 3

May be you've miss your real results:

$arr=array("a","a","b","c","d");
$arrs=array_count_values($arr);
/*
now $arrs is:
array (
  'a' => 2,
  'b' => 1,
  'c' => 1,
  'd' => 1,
)
*/

foreach($arrs as $id => $count){
 if($count==1) {
   // do your code
 }
}

/*******************************************************/
/* usefull version                                     */
/*******************************************************/

$arr=array("a","a","b","c","d");
$arrs=array_count_values($arr);


foreach($arr as $id ){
 if($arrs[$id]==1){ 
   // do your code
   echo "$id is single\n";
 }
}

Answer 4

You just need to retrieve any value which only occurs once in the array, right? Try this:

$arr=array("a","a","b","c","d");
$arrs=array_count_values($arr);

foreach ($arrs as $uniqueValue => $count)
{
  if($value == 1) {
    echo $uniqueValue; 
  }
}

array_count_values returns an associative array where the key is the value found and its value is the number of times it occurs in the original array. This loop simply iterates over each unique value found in your array (i.e. the keys from array_count_values) and checks if it was only found once (i.e. that key has a value of 1). If it does, it echos out the value. Of course, you probably want to do something a bit more complex with the value, but this works as a placeholder.

Answer 5

$count = 0;
foreach(array("a","a","b","c","d") as $v){
    if($v == 1){$count++;}
}