PHP code in an input text-box value doesn't generate PHP code

Question

I have a file called form.php which is just a regular html file with the addition of the following:

<form>
<input type="text" value="<?php if(!empty($_GET['type'])) {echo(htmlspecialchars($_GET['type']));} ?>" />
</form>

The problem is that when I open the file, the actual PHP code itself is displayed in the text field, instead of getting the variable 'type.' How do I solve this?

do you have it saved as a php file? are you running it via a php compatible server? (apache etc...) — mreq
– mreq, Commented Sep 4, 2011 at 20:03
I just tried to run it locally in my browser. I'm now going to upload it to my website and test it. — DLA
– DLA, Commented Sep 4, 2011 at 20:05
if you want to test it locally, you can set up XAMPP to create a functional webserver on your localhost. ;) — Andreas Grapentin
– Andreas Grapentin, Commented Sep 4, 2011 at 20:13

genesis · Accepted Answer · 2011-09-04 20:04:09Z

0

PHP module is not loaded or not installed. Check your server's configuration

answered Sep 4, 2011 at 20:04

genesis

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oh, right. that could make sense. i was just trying to test it locally.

DLA
– DLA

09/04/2011 20:05:23
Commented Sep 4, 2011 at 20:05

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Nexerus · Accepted Answer · 2011-09-04 20:06:06Z

0

You say the code is in a "regular html file", does that mean the file is, for example, "myfile.html"? If so, rename it to "myfile.php" and that should solve your problem.

answered Sep 4, 2011 at 20:06

Nexerus

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