up vote 1 down vote favorite 
$i = 1
echo '
<p class="paragraph$i">
</p>
'
++i

Trying to insert a variable into an echoed string. The above code doesn't work. How do I iterate a php variable into an echo string?

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6 Answers

up vote 11 down vote accepted

Single quotes will not parse PHP variables inside of them. Either use double quotes or use a dot to extend the echo.

$variableName = 'Ralph';
echo 'Hello '.$variableName.'!';

OR

echo "Hello $variableName!";

And in your case:

$i = 1;
echo '<p class="paragraph'.$i.'"></p>';
++i;

OR

$i = 1;
echo "<p class='paragraph$i'></p>";
++i;
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I suppose only the first would work for my instance as the variable is not separated from the word. – Mechaflash Nov 8 '11 at 18:03
1  
No, it shouldn't matter, as the second one isn't outputting any space between "paragraph" and the output of the variable. – Doctor Trout Nov 8 '11 at 18:05
The 3rd won is what works for me. But I do understand the difference between double and single quotes. Just that I'm editing an open source program to make some minor customizations and I don't want to change the formatting around too much. – Mechaflash Nov 8 '11 at 18:19
up vote 4 down vote

Variable interpolation does not happen in single quotes. You need to use double quotes as:

$i = 1
echo "<p class=\"paragraph$i\"></p>";
++i;
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up vote 4 down vote 
echo '<p class="paragraph'.$i.'"></p>'

should do the trick.

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up vote 3 down vote 
echo '<p class="paragrah"' . $i . '">'
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up vote 3 down vote 
echo '<p class="paragraph'.$i.'"></p>';
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up vote 1 down vote

Use double quotes:

$i = 1;
echo "
<p class=\"paragraph$i\">
</p>
";
++i;
share|improve this answer

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