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I have an array in PHP, which I pack to JSON object with _json_encode(..)_ . Then I send it to JS function as parameter. When I want to parse the object in Javascript with eval(..) nothing happens (there is an error behind the curtains I guess). What could be wrong?
Code:

<script type="text/javascript">
    function testFun(inArr) {
      var obj=eval('('+inArr+')');
      alert(obj.m); //alert(obj) also doesnt work
    }
</script>  


//PHP
$spola_array = array('m' => 1, 'z' => 2);
$json_obj=json_encode($spola_array);
echo '<script type="text/javascript">testFun('.$json_obj.');</script>';
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1 Answer

up vote 4 down vote accepted

It's already parsed since you're outputting it as an object literal and not a string. That will look like:

<script type="text/javascript">testFun({m: 1, z: 2});</script>

So in your function, it's just:

alert(inArr.m) //1

You would only need to parse it if it were a string:

<script type="text/javascript">testFun('{m: 1, z: 2}');</script>
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BIG thanks for this one. Couldn't figure it out in past hours. – Primož 'c0dehunter' Kralj May 27 '12 at 21:46
No problem. Sometimes it can help to debug things like this with console.log by the way. It typically provides a better formatted output than alerts. – Corbin May 27 '12 at 21:49
Where is this console.log? Edit: do you mean Firebug? I've never used it before and maybe I should start :) – Primož 'c0dehunter' Kralj May 27 '12 at 21:50
It's just a function the dev tools of Chrome and IE expose, and a function exposed by Firebug in Firefox. You just use it like console.log("test!"); or console.log(someVar); It's not meant to be used in production code. It's just a slightly more useful way of doing alert(someVar). It typically includes a little bit of information about the type of variable, and in the case of object literals, it will show that they are objects and show which keys are defined. – Corbin May 27 '12 at 21:52
Thanks, great piece of advice. – Primož 'c0dehunter' Kralj May 27 '12 at 21:53

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