Postgres Query of an Array using LIKE

Question

I am querying a database in Postgres using psql. I have used the following query to search a field called tags that has an array of text as it's data type:

select count(*) from planet_osm_ways where 'highway' = ANY(tags);

I now need to create a query that searches the tags fields for any word starting with the letter 'A'. I tried the following:

select count(*) from planet_osm_ways where 'A%' LIKE ANY(tags);

This gives me a syntax error. Any suggestions on how to use LIKE with an array of text?

Answer 1

Use the unnest() function to convert array to set of rows:

SELECT count(distinct id)
FROM (
    SELECT id, unnest(tags) tag
    FROM planet_osm_ways) x
WHERE tag LIKE 'A%'

The count(dictinct id) should count unique entries from planet_osm_ways table, just replace id with your primary key's name.

That being said, you should really think about storing tags in a separate table, with many-to-one relationship with planet_osm_ways, or create a separate table for tags that will have many-to-many relationship with planet_osm_ways. The way you store tags now makes it impossible to use indexes while searching for tags, which means that each search performs a full table scan.

Answer 2

Here is another way to do it within the WHERE clause:

SELECT COUNT(*)
FROM planet_osm_ways 
WHERE (
  0 < (
    SELECT COUNT(*) 
    FROM unnest(planet_osm_ways) AS planet_osm_way
    WHERE planet_osm_way LIKE 'A%'
  )
);

Answer 3

this is how i managed to do it :

select id from products where (exists (select ut from (select unnest(tags) as ut) as tmp1 where ut like '%that%'))