current community

more stack exchange communities

Stack Exchange
tour help
careers 2.0
Take the 2-minute tour ×
Stack Overflow is a question and answer site for professional and enthusiast programmers. It's 100% free, no registration required.
up vote 2 down vote favorite

Let us say I have an object Airport with members airportCode and airportCity like this: 

function Airport(airportCode, airportCity) {
        this.airportCode = airportCode;
        this.airportCity = airportCity;
    };

How can I create an array of objects Airport to which I can add. In Java, this would work like this: 

while(st.hasMoreTokens()) {
    Airport a = new Airport();
    a.airportCode = st.nextToken();
    a.airportCity = st.nextToken();
    airports.add(a);
}
share|improve this question
2  
Create an array using var airports = [];. Then, in the loop, create an Airport instance, and add it to the array using the airports.push method. –  Rob W Jul 17 '12 at 21:12
 
What is st in your javascript code? –  Bergi Jul 17 '12 at 21:15
add comment

3 Answers

up vote 2 down vote accepted

A very short answer: 

airports.push(new Airport("code","city"));
share|improve this answer
add comment
up vote 3 down vote

Try this:

function Airport(airportCode, airportCity) {
        this.airportCode = airportCode;
        this.airportCity = airportCity;
};

var dataArray = [];

for(var i=0; i< 10; i++){
    dataArray[i] = new Airport("Code-" + i, "City" + i);
}
share|improve this answer
1  
Or simply dataArray.push(new Airport(...)); which is slightly faster. :-) –  YMMD Jul 17 '12 at 21:22
1  
Index based acces is better than push for performance –  Chandu Jul 17 '12 at 21:24
1  
No, push() is faster. ;) Try it yourself: jsperf.com/index-vs-push –  YMMD Jul 17 '12 at 21:25
1  
here's another jsperf.com/push-vs-index-2 To show that it's much easier to write as well. –  Esailija Jul 17 '12 at 21:28
 
I take back my previous comment since the results are not consistent across browsers/os. –  Chandu Jul 18 '12 at 11:56
add comment
up vote 2 down vote

It's not really that different

var airports = [];
while (st.hasMoreTokens()) {
    var a = new Airport();
    a.airportCode = st.nextToken();
    a.airportCity = st.nextToken();
    airports.push(a);
}
share|improve this answer
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.