up vote 4 down vote favorite

Say I have an array: [0,3,4,2,5,1] What i want to do is sort an array such as: ["one", "two", "three", "four", "five", "six"] so that the order corresponds to the first array. This would be the output: ["one", "four", "five", "three", "six", "two"]

Is there an easy way to accomplish this?

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92% accept rate
Your question is confusing, since it has got nothing to do with sorting. You keep the array in the same order, just map each element of the array to an element of another array. – Amnon Oct 28 '10 at 21:20
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4 Answers

up vote 8 down vote accepted

You can do something like this:

function getSorted(arr, sortArr) {
  var result = [];
  for(var i=0; i<arr.length; i++) {
    result[i] = arr[sortArr[i]];
  }
  return result;
}

You can test it out here.

Note: this assumes the arrays you pass in are equivalent in size, you'd need to add some additional checks if this may not be the case.

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Thanks Nick, this works perfectly! – Sarathi Oct 28 '10 at 21:54
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up vote 0 down vote

Not sur how you get your first array, but you could use an array of objects instead of [0,3,4,2,5,1]:

var arr = [
  {n:0, s:'one'},
  {n:3, s:'four'},
  {n:4, s:'five'},
  {n:2, s:'three'},
  {n:5, s:'six'},
  {n:1, s:'two'}
]

And avoid to process it.

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up vote 0 down vote 
orderedArray= function(arr,order){
    return  order.map(function(itm){return arr[itm]});
}

var sequence= [0, 3, 4, 2, 5, 1],arr=["one","two","three","four","five","six"]

arr=new orderedArray(arr,sequence);

/*  returned value: (Array)
one,four,five,three,six,two
*/

//You can make the order an unindexed property of the array, // and call array.ordered()

Array.prototype.ordered= function(order){
    var arr= this;
    order=order || this.order;
    return order.map(function(itm){
        return arr[itm];
    });
}


var arr= ["one","two","three","four","five","six"],
sequence= [0, 3, 4, 2, 5, 1];

arr.order=sequence;

arr.ordered()

/*  returned value: (Array)
one,four,five,three,six,two
*/
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up vote 0 down vote 
class test1
{
  public static String[] sort(int[] array,String[] str)
  {
    String[] out=new String[str.length];
    for(int i=0;i<str.length;i++)
    {
      out[i]=str[array[i]];
    }
    return out;
  }
}
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