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up vote 1 down vote favorite

Is the following code correct?

 $.ajax( {
             url: './ajax/ajax_addTerms.php',
             type: 'POST',
             data: {"fId" : $fId, "term" : $term, "alias" : $alias,
 "userId" : <?php  print $userId; ?>},

When I remove the PHP tags it works, but this way it doesn't.

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I think the word by ajax is wrongly stated. You probably mean how to create JavaScript Ajax query at from PHP. – Shamim Hafiz Dec 22 '10 at 14:29
It probably does not "work" without <?php. But the JavaScript engine won't throw an error. – Felix Kling Dec 22 '10 at 14:30
Why are you data keys in quotes? – Mikhail Dec 22 '10 at 15:33

4 Answers

up vote 3 down vote accepted

Wrap the value like this:

 "userId" : "<?php  print $userId; ?>"}

Otherwise JS will try to parse the PHP output which is wrong.

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if the userid is numeric it'll work without outside quotation – Mikhail Dec 22 '10 at 15:32
up vote 2 down vote 
 $.ajax( {
             url: './ajax/ajax_addTerms.php',
             type: 'POST',
             data: {"fId" : <?php echo $fId ?>, "term" : "<?php echo $term ?>", "alias" : "<?php echo $alias ?>",
 "userId" : <?php echo $userId; ?>},
 // echo is faster than print
 // and I assume $fId and $userId are integers so quotes aren't required

PHP's interpreter will parse variables and then JS does the rest.

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up vote 1 down vote

I would use json_encode additionally to the <?php ?> to make sure that " in a string gets escaped properly:

data: {"fId" : <?php echo json_encode($fId); ?>, "term" : <?php echo json_encode($term) ?>, "alias" : <?php echo json_encode($alias); ?>, "userId" : <?php echo $userId; ?>},

This way, you could also pass an array:

<?php $data = array('fId' => $fId, 'term' => $term, 'alias' => $alias, 'userId' => $userId); ?>
...
data: <?php echo json_encode($data); ?>, // Same result as above
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up vote 1 down vote

JavaScript is client side, PHP is server side. Ajax works like this,

JavaScript HTTP request --> PHP --> return request that is catched by the Ajax handler.

You can't start Ajax from the server side.

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Wrong way round: JS is client side, PHP is server side :P – Kyle Hudson Dec 22 '10 at 14:34
Haha I failed :$ – Mark Dec 22 '10 at 15:50

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