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Here is the php array i am using. I am trying to convert each entry into a string and pass it to the javascript variable, but when i use the following code I only get the first letter of each word in the php array.

<?php 
$terms = array('cat', 'dog', 'bird');
$rand_keys = array_rand($terms);
?>

Javascript variable with php array data

var searchterms = <?php echo json_encode($terms[$rand_keys]); ?>;
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you want to create a js variable for each element of php array or any one js variable for random php array element. – Gaurav Feb 8 '11 at 19:08

2 Answers

up vote 2 down vote

use shuffle($terms); then echo json_encode( $terms );

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this works great but when what if i wanted to dd many more terms to the php array. i looked at the source and it displays all the terms like this var searchterms = ["slamjam","kenny","opp","heel","dog","bird","lol","flip","aaa","juu","sam","ste‌​rn","ben","upndon","cat"]; is there any way to make it display one term at a time? – Dan Feb 8 '11 at 19:20
@Dan are you converting searchterms to a json object? – Andrew Jackman Feb 8 '11 at 19:29
no, should I do that? – Dan Feb 8 '11 at 19:35
@Dan yup :) since it is a trusted source you can use eval(), then you can navigate the json object similar to an array (searchterms[0] will show the first value) – Andrew Jackman Feb 8 '11 at 19:37
up vote 1 down vote

The following code just take a random element from the php array and not the whole array:
var searchterms = <?php echo json_encode($terms[$rand_keys]); ?>;

Use the following code to get all the elemenets:
var searchterms = <?php foreach ($terms as $t){echo json_encode($t);} ?>

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thank you but i need the terms to echo back randomly – Dan Feb 8 '11 at 19:22

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