use variable from php as an alert for javascript

Question

how can i use the variable from my php-sql to become the message for my javascript alert?

heres my code

<?php

    $select = "SELECT * FROM post";
    $result = mysql_query($select) or die("couldn't select table");


    while ($rows = mysql_fetch_array($result))
    {
        echo"<input type='button' class=term onclick='return terms()' value=Terms >";

        echo"<input type='hidden' value='$rows[terms]' id='term' name='term'>";
    }
?>  

<script language="JavaScript">
    function terms() 
    {
        var readers = document.getElementById("term"); 
        alert(readers.value);
    }
</script>

It works, the alert message displays. But I got the problem on displaying the right message for specific fetch of row. All got the same message (message from the first row).

I tried to use getElementByName but the alert doesn't pop-up, so i dont have to try making the input name="term[]" --------(into its array form)

Help please!

Justin John · Accepted Answer · 2012-07-22 02:53:56Z

up vote 1 down vote accepted

I think it will be find if you change this line of script

 echo"<input type='button' class=term onclick='terms()' value=Terms >";

onclick='terms()' here, instead of onclick='return terms()'

EDIT:

<?php   echo"<input type='button' class=term onclick='terms(this)' data-result ='". $rows['terms'] ."' value=Terms >"; ?>
      /* Remove the hidden field */
<script language="JavaScript">
    function terms(e) 
    {
        var readers = e.getAttribute('data-result'); 
        alert(readers);
    }
</script>

edited Jul 22 '12 at 2:53

answered Jul 21 '12 at 9:25

Justin John
1,74711038

	i changed, but alert doesn't showed when i used getElementByName – ivory- santos Jul 21 '12 at 9:49
	@ivory- santos: Check the console... Any error? – Justin John Jul 21 '12 at 9:52
	sorry i don't know what you mean console is... newbie here – ivory- santos Jul 21 '12 at 9:58
	@ivory- santos: check my updated answer... – Justin John Jul 21 '12 at 10:23
	Thank you so much @JustinJohn it works! – ivory- santos Jul 23 '12 at 1:47

show 2 more comments

Ahmad · Answer 2 · 2012-07-21 09:21:26Z

up vote 0 down vote

You are overwriting the value or "term" in your HTML code after each iteration of While-loop. This way it will only get the last value

answered Jul 21 '12 at 9:21

Ahmad
2,619426

pat34515 · Answer 3 · 2012-07-21 09:21:32Z

up vote 1 down vote

Change your second echo statement inside the while loop to:

echo"<input type='hidden' value='". $rows['terms'] ."' id='term' name='term'>";

answered Jul 21 '12 at 9:21

pat34515
1,27119

Michael Krelin - hacker · Answer 4 · 2012-07-21 09:22:18Z

up vote 0 down vote

All of your input elements have the same id. If you want to distinguish them, give them different identifiers. And pass the identifier to the terms function.

answered Jul 21 '12 at 9:22

Michael Krelin - hacker
38.3k5384

infinitecolon · Answer 5 · 2012-07-21 09:27:06Z

up vote 0 down vote

I usually do the following:

<?php
  function alert($text){
    echo '<script type="text/javascript">alert("'.$text.'")</script>';
  }

  alert("test");
?>

Hope that helps.

answered Jul 21 '12 at 9:27

infinitecolon
905

	i dont get it, is "test" diff from "$text" ? – ivory- santos Jul 21 '12 at 9:44
	$text is a variable, "test" is the value that you set $text to. – infinitecolon Jul 22 '12 at 8:55

defiana sulaeman · Answer 6 · 2012-07-21 10:25:10Z

up vote 0 down vote

You must give different id for each element. I think simple way to do that is by using auto increment for the id.

answered Jul 21 '12 at 10:25

defiana sulaeman
657

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use variable from php as an alert for javascript

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