up vote 2 down vote favorite

I am trying this code:

<script type="text/javascript">
for (i = 0; i < 5; i++) {
    for (x = 0; x < 1; x++) {
        $("#one" + i).html("<?php echo $arr["+i+"]["+x+"] ?>");
        $("#two" + i).html("<?php echo $arr["+i+"]["+x+1+"] ?>");
    };
};

</script>

No error is showed, but content also not.

How can I use the increment variable of JavaScript in PHP code?

Thanks

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Just to say, this line for (x = 0; x < 1; x++) is egual than simply write x = 0 and delete the inner loop. – Aurelio De Rosa Oct 21 '11 at 23:29

4 Answers

up vote 7 down vote accepted

You may make your PHP-array accessible to JS(store it as a js-variable) :

<script type="text/javascript">
var arr=<?php echo json_encode($arr); ?>;
for (i = 0; i < arr.length; i++) {
    for (x = 0; x < 1; x++) {
        $("#one" + i).html(arr[i][x]);
        $("#two" + i).html(arr[i][x+1]);
    };
};
</script>
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your code gives me this error: arr[i] is undefined – Daniel Oct 21 '11 at 23:43
Please show the output of json_encode($arr) – Dr.Molle Oct 21 '11 at 23:44
the output is: [["A","B"],["C","D"],["E","F"]] - thanks – Daniel Oct 21 '11 at 23:47
Your loop runs from 0 to 4, but there are only 3 items. You'll get an error when i comes to 3(arr[3] doesn't exist). See my updated code, use arr.length instead of the fixed 5 to avoid this error. – Dr.Molle Oct 22 '11 at 0:42
up vote 7 down vote

You cannot do this.

Javascript runs on the client, which is after all PHP code has executed.

Why don't you write the loop in PHP instead? For example,

<script type="text/javascript">
<?php
for ($i = 0; $i < 5; $i++) {
    for ($x = 0; $x < 1; $x++) {
        printf('$("#one%s").html("%s");', $i, $arr[$i][$x]);
        printf('$("#two%s").html("%s");', $i, $arr[$i][$x + 1]);
    };
};
?>
</script>
share|improve this answer
Jon, i am totally confused. The only thing that i know is that i have a group of divs like #one0, #two0, #one1, #one1, ... and none of them changes the text to display. The other thing that i know is: echo $arr[0][0] or $arr[0][1] returns a value – Daniel Oct 22 '11 at 0:38
@Daniel: There are so many unknowns in this situation, and you are obviously at the beginner stage, that it's really difficult to tell what's wrong. The code should work, but you may have some issues with setting up jQuery right. What about writing the code to change the contents literally (forgetting about $arr)? Does that work? What about $arr? Does it have enough elements? – Jon Oct 22 '11 at 0:49
the problem is the word sprintf, must be printf. With this change also works now. thanks – Daniel Oct 22 '11 at 1:19
@Daniel: Doh. Intended to write echo sprintf, then realized that just printf is the same, and made only half of the edit. Sorry for that. – Jon Oct 22 '11 at 1:24
thanks for the lesson :) – Daniel Oct 22 '11 at 1:25
up vote 0 down vote

Ok, I try to give you a short question..althought it may be very long. PHP it's a Server-side scripting language, while javascript it's a Client-side one.

That's mean that the php code is interpreted and executeted in the server (e.g. Apache), and the javascript code is executed inside the browser itself.

So, there is no way you can execute php code inside of your brower. for the code you have written you can simpli transform the two for javascript iteration in php. If you actually need to print something in php given a javascript variable you should do an AJAX request to a php page that recive your javascript value and returns back the php-calculated values you need.

Please have a look at those references as a start:

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up vote 0 down vote

<?php is interpreted by the php interpreter. If you don't have this block in an actual php file, then that means you are executing in the context of the browser. The browser doesn't know about php, only your web server. Thus, the browser will interpret <?php as an HTML element, which doesn't exist.

You need to move your entire block into a php file, like so:

myFile.php
==========
    <?php
        $arr = array(...);
        $arrLen = count($arr);
        $output = '<script type="text/javascript">';
        for ($i=0; $i<$arrLen; $i++) {  // notice this is in php, not js
            $output .= '$("#one"'.$i.').html("'.$arr[$i][0].'");';
            $output .= '$("#two"'.$i.').html("'.$arr[$i][1].'");';
        }
        $output .= '</script>';
        echo $output;
    ?>
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