Syntax error in a bash script that calls find

Strings in single quotes are not interpolated. It means, you are trying to run

find ' ${rep} '-type f

Remove the single quotes. If you really need to quote the $rep (e.g. because it contains spaces), use double quotes:

files=`find "$rep" -type f`

Note that there are no spaces inside the double quotes. You are searching 'git', not ' git ', right?

Don't store the output of find in a variable. It's unreliable and inefficient. Inefficient, because find has to finish running before you start processing its output; this makes a difference on a large directory tree. Unreliable because even if you got the command syntax right, the output of find would consists of a list of file names separated by newlines. This is ambiguous unless the file names are known not to contain newlines. Furthermore, you aren't parsing the output correctly: with an unquoted command substitution $(…), the result of the command is broken into separate words wherever there's whitespace (not just newlines), and the words are interpreted as shell glob patterns. To avoid this processing, use "$(…)" (always put double quotes around variable and command substitutions: "$foo", "$(foo)"); this is no good here since you need to separate the file names.

find has a built-in feature to process the resulting files: the -exec action. Use it. That's what it's for.

find "$rep" -type f -exec echo {} \;

If you need to run an arbitrary shell snippet and not just a single command on each file, invoke a shell as the command. To avoid mangling the file name, pass it as a parameter to the shell.

find "$rep" -type f -exec sh -c '
  echo "$0"
  # more shell commands ...
' {} \;

Add space after ' and before -type