mysql_field_seek

mysql_field_len

[edit] Last updated: Fri, 29 Jun 2012

mysql_field_name

(PHP 4, PHP 5)

mysql_field_name — Get the name of the specified field in a result

Description

string mysql_field_name ( resource $result , int $field_offset )

mysql_field_name() returns the name of the specified field index.

Parameters

result: The result resource that is being evaluated. This result comes from a call to mysql_query().
field_offset: The numerical field offset. The field_offset starts at 0. If field_offset does not exist, an error of level E_WARNING is also issued.

Return Values

The name of the specified field index on success or FALSE on failure.

Examples

Example #1 mysql_field_name() example


<?php
/* The users table consists of three fields:
 *   user_id
 *   username
 *   password.
 */
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
    die('Could not connect to MySQL server: ' . mysql_error());
}
$dbname = 'mydb';
$db_selected = mysql_select_db($dbname, $link);
if (!$db_selected) {
    die("Could not set $dbname: " . mysql_error());
}
$res = mysql_query('select * from users', $link);

echo mysql_field_name($res, 0) . "\n";
echo mysql_field_name($res, 2);
?>

The above example will output:

user_id
password

Notes

Note: Field names returned by this function are case-sensitive.

Note:
For backward compatibility, the following deprecated alias may be used: mysql_fieldname()


simple sql to xml converter works with any sql query and returns the name of the table as the root element "row" as each row element and the names of the columns are your children of row. fully tested.





<?php


function sqlToXml($host,$user,$pass,$database,$tablename,$query){





    $link   = mysql_connect($host, $user, $pass) or die("Could not connect: " . mysql_error());


    $db     = mysql_select_db($database, $link) or die(mysql_error());


    


    $result = mysql_query($query);


    if(!$result){ die('Invalid query: '.mysql_error()); }


    


    $numOfCols = mysql_num_fields($result);


    $numOfRows = mysql_num_rows($result);


    


    $info = mysql_fetch_assoc($result);


    


    //send headers


    header('Content-type: text/xml');


    header('Pragma: public');        


    header('Cache-control: private');


    header('Expires: -1');


    $xml = '<?xml version="1.0" encoding="utf-8"?>';


    $xml.= "<{$tablename}>";


    


    if($numOfRows > 0){


        do {


            $xml.= "<row>";


            foreach($info as $column => $value) {


                $xml.= "<{$column}>{$value}</{$column}>";


            }


            $xml.= "</row>";


        }


        while ($info = mysql_fetch_array($result));


    }


    $xml.= "</{$tablename}>";


    


    mysql_free_result($result);    


    return $xml;


    


}


?>

bags 24-Jul-2010 09:02


When using aliases, it appears impossible to discover the name of the underlying column.

select `ID` as `anAlias` from `aTable` returns 'anAlias' as the mysql_field_name(). I have tried all the mysql_field_xxx() functions and none return the real column name.

anonymous at site dot com 08-Mar-2008 11:13


This function is slightly stupid to be honest, why not just make an array of field names... You could consolidate the two of these functions that way and it makes it a lot easier to list them when your script is dynamic.



<?php



    function mysql_field_array( $query ) {

    

        $field = mysql_num_fields( $query );

    

        for ( $i = 0; $i < $field; $i++ ) {

        

            $names[] = mysql_field_name( $query, $i );

        

        }

        

        return $names;

    

    }

    

    // Examples of use

    

    $fields = mysql_field_array( $query );

    

    // Show name of column 3

    

    echo $fields[3];

    

    // Show them all

    

    echo implode( ', ', $fields[3] );

    

     // Count them - easy equivelant to 'mysql_num_fields'

    

    echo count( $fields );



?>

blackjackdevel at gmail dot com 13-Nov-2007 09:13


Strangely using an aproach like this:

$res=mysql_query("SELECT * FROM `orders`",$conec) or die (mysql_error());



$fields = mysql_num_fields($res);

$out="";

for ($i = 0; $i < $fields; $i++) {

    $fname=mysql_field_name($res, $i);



}



 Outputted the E_Warning:

Warning: mysql_field_name() [function.mysql-field-name]: Field N is invalid for MySQL result index 



 With a lot of different number at N. But expliciting all fields instead of *. Didn't outputted the error.



 It maybe a caracteristic of this mysql database(it is from a open source application) because i never saw this in my own databases. Anyway hope this help if someone face the same strange situation

matteo.cisilino[no_more]cisilino[spm]com 09-Jan-2007 01:54


james, why make so difficult when it's very simple :\



$numberfields = mysql_num_fields($res_gb);



   for ($i=0; $i<$numberfields ; $i++ ) {

       $var = mysql_field_name($res_gb, $i);

       $row_title .= $var;

   }



echo $row_title;

janezr at jcn dot si 19-Oct-2005 01:18


This is another variant of displaying all columns of a query result, but with a simplified while loop.



<?

$query="select * from user";

$result=mysql_query($query);

$numfields = mysql_num_fields($result);



echo "<table>\n<tr>";



for ($i=0; $i < $numfields; $i++) // Header

{ echo '<th>'.mysql_field_name($result, $i).'</th>'; }



echo "</tr>\n";



while ($row = mysql_fetch_row($result)) // Data

{ echo '<tr><td>'.implode($row,'</td><td>')."</td></tr>\n"; }



echo "</table>\n"

?>

clinnenb at hotmail dot com 05-Aug-2005 02:19


The following will create a PHP array, $array, containing the MySQL query results with array indexes of the same name as field names returned by the MySQL query.



while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {

    $i=0;

    foreach ($line as $col_value) {

        $field=mysql_field_name($result,$i);

        $array[$field] = $col_value;

        $i++;

    }

}

jimharris at blueyonder dot co dot uk 19-Dec-2004 11:28


The code in the last comment has an obvious mistake in the for loop expression.  The correct expression in the for-loop is $x<$y rather than $x<=$y...



$result = mysql_query($sql,$conn) or die(mysql_error());

$rowcount=mysql_num_rows($result);

$y=mysql_num_fields($result);

for ($x=0; $x<$y; $x++) {

   echo = mysql_field_name($result, $x).'<br>';

}

colin dot truran at shiftf7 dot com 16-Dec-2004 09:44


T simply itterate through all the field names on a result set try using this.



$result = mysql_query($sql,$conn) or die(mysql_error());

$rowcount=mysql_num_rows($result);

$y=mysql_num_fields($result);

for ($x=0; $x<=$y; $x++) {

    echo = mysql_field_name($result, $x).'<br>';

}



This is useful if you have a result set that joins several tables dynamicaly and you are never sure what all the fields will be when you come to display them.



I suggest you place this within a loop through your result rows and include a field flag check  around the echo to only show certain data types like this.



$y=mysql_num_fields($result);

while ($row=mysql_fetch_array($result)) {

  for ($x=0; $x<=$y; $x++) {

    $fieldname=mysql_field_name($result,$x);

    $fieldtype=mysql_field_type($result, $x);

    if ($fieldtype=='string' && $row[$fieldname]!='')    

       echo $row[$fieldname].' , ';

   }

   echo '<br>';

}

aaronp123 att yahoo dott comm 20-Feb-2003 11:27


You could probably elaborate on this by sending a full sql query to this function...but I titled it simple_query() because it doesn't really allow for joins.  Never the less, if you want to get a quick array full of a single row result set this is painless:



function simple_query($table_name, $key_col, $key_val) {

    // open the db

    $db_link = my_sql_link();

    // query table using key col/val

    $db_rs = mysql_query("SELECT * FROM $table_name WHERE $key_col = $key_val", $db_link);

    $num_fields = mysql_num_fields($db_rs);

    if ($num_fields) {

        // first (and only) row

        $row = mysql_fetch_assoc($db_rs);

        // load up array

        for ($i = 0; $i < $num_fields; $i++) {

            $simple_q[mysql_field_name($db_rs, $i)] = $row[mysql_field_name($db_rs, $i)];

        }

        // and return

        return $simple_q;

    } else {

        // no rows

        return false;

    }

    mysql_free_result($db_rs);

}



**Please note that my_sql_link() is just a function I have to open up a my sql connection.**

jason dot chambes at phishie dot net 20-Feb-2003 11:07


<?

/*

    By simply calling the searchtable() function

    with these variables it will serach the desired

    database and procude a table for each field that

    there is a match.

*/



function searchtable($host,$user,$pass,$database,$tablename,$userquery)

{

    $link   = mysql_connect($host, $user, $pass) or die("Could not connect: " . mysql_error());

    $db     = mysql_select_db($database, $link) or die(mysql_error());

    $fields = mysql_list_fields($database, $tablename, $link);

    $cols   = mysql_num_fields($fields);



    for ($i = 1; $i < $cols; $i++) {

        $allfields[] = mysql_field_name($fields, $i);

    }

    foreach ($allfields as $myfield) {

        $result = mysql_query("SELECT * FROM $tablename WHERE $myfield like '%$userquery%' ");

        if (mysql_num_rows($result) > 0){

            echo "<h3>search <i>$database</i> for <i>$userquery</i>, found match(es) in <i>$myfield</i>: </h3>\n";

            echo "<table border=1 align=\"center\">\n\t<tr>\n";

            for ($i = 1; $i < $cols; $i++) {

                echo "\t\t<th";

                if ($myfield == mysql_field_name($fields, $i)){

                    echo " bgcolor=\"orange\"> ";

                } else {

                    echo ">";

                }

                echo mysql_field_name($fields, $i) . "</th>\n";

            }

            echo "\t</tr>\n";

            $myrow = mysql_fetch_array($result);

            do {

                echo "\t<tr>\n";

                for ($i = 1; $i < $cols; $i++){

                    echo "\t\t<td> $myrow[$i] &nbsp;</td>\n";

                }

                echo "\t</tr>\n";

            } while ($myrow = mysql_fetch_array($result));

            echo "</table>\n";

        }

    }

}



searchtable($host,$user,$pass,$database,$tablename,$userquery);

?>

matt at iwdt dot net 23-Sep-2001 12:09


here's one way to print out a row of <th> tags from a table


NOTE: i didn't test this





$result = mysql_query("select * from table");





for ($i = 0; $i < mysql_num_fields($result); $i++) {


    print "<th>".mysql_field_name($result, $i)."</th>\n";


}





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