std::merge
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Заголовочный файл <algorithm>
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template< class InputIt1, class InputIt2, class OutputIt > OutputIt merge( InputIt1 first1, InputIt1 last1, |
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template< class InputIt1, class InputIt2, class OutputIt, class Compare> OutputIt merge( InputIt1 first1, InputIt1 last1, |
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[first1, last1)
и [first2, last2)
в один отсортированный диапазон начало в d_first
. Первый вариант используется operator< для сравнения элементов, вторая версия использует данную comp
функцию сравнения. Относительный порядок эквивалентных элементов сохраняется.[first1, last1)
and [first2, last2)
into one sorted range beginning at d_first
. The first version uses operator< to compare the elements, the second version uses the given comparison function comp
. The relative order of equivalent elements is preserved.You can help to correct and verify the translation. Click here for instructions.
Содержание |
[править] Параметры
first1, last1 | - | первый ряд элементов для слияния
Original: the first range of elements to merge The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
first2, last2 | - | второй ряд элементов для слияния
Original: the second range of elements to merge The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
d_first | - | В начале назначения диапазона
Original: the beginning of the destination range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. | |||||||||
Type requirements | |||||||||||
-InputIt1 must meet the requirements of InputIterator .
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-InputIt2 must meet the requirements of InputIterator .
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-OutputIt must meet the requirements of OutputIterator .
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[править] Возвращаемое значение
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[править] Сложность
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[править] Возможная реализация
First version |
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template<class InputIt1, class InputIt2, class OutputIt> OutputIt merge(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first) { for (; first1 != last1; ++d_first) { if (first2 == last2) { return std::copy(first1, last1, d_first); } if (*first2 < *first1) { *d_first = *first2; ++first2; } else { *d_first = *first1; ++first1; } } return std::copy(first2, last2, d_first); } |
Second version |
template<class InputIt1, class InputIt2, class OutputIt, class Compare> OutputIt merge(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp) { for (; first1 != last1; ++d_first) { if (first2 == last2) { return std::copy(first1, last1, d_first); } if (comp(*first2, *first1)) { *d_first = *first2; ++first2; } else { *d_first = *first1; ++first1; } } return std::copy(first2, last2, d_first); } |
[править] Пример
#include <iostream> #include <iterator> #include <cstdlib> #include <algorithm> #include <vector> int main() { const std::size_t items = 10; std::vector<int> v1, v2, dst; // fill the vectors for (std::size_t idx = 0; idx < items; ++idx) { v1.push_back(std::rand()%items); v2.push_back(std::rand()%items); } // sort std::sort(v1.begin(), v1.end()); std::sort(v2.begin(), v2.end()); // output v1 std::cout << "v1 : "; std::copy(v1.begin(), v1.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; // output v2 std::cout << "v2 : "; std::copy(v2.begin(), v2.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; // merge std::merge(v1.begin(), v1.end(), v2.begin(), v2.end(), std::back_inserter(dst)); // output std::cout << "dst: "; std::copy(dst.begin(), dst.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; }
Вывод:
v1 : 0 0 2 2 3 3 3 6 7 9 v2 : 1 2 5 5 6 6 6 6 7 9 dst: 0 0 1 2 2 2 3 3 3 5 5 6 6 6 6 6 7 7 9 9
[править] См. также
объединяет два приказал диапазонов на месте Original: merges two ordered ranges in-place The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) | |
виды диапазон в порядке возрастания Original: sorts a range into ascending order The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) | |
виды диапазон элементов при сохранении порядка между равными элементами Original: sorts a range of elements while preserving order between equal elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) |