std::min_element
Материал из cppreference.com
![]() |
This page has been machine-translated from the English version of the wiki using Google Translate.
The translation may contain errors and awkward wording. Hover over text to see the original version. You can help to fix errors and improve the translation. For instructions click here. |
Заголовочный файл <algorithm>
|
||
template< class ForwardIt > ForwardIt min_element( ForwardIt first, ForwardIt last ); |
(1) | |
template< class ForwardIt, class Compare > ForwardIt min_element( ForwardIt first, ForwardIt last, Compare comp ); |
(2) | |
Находит наименьший элемент в диапазоне
[first, last)
. Первый вариант используется operator< для сравнения значений, вторая версия использует данную функцию сравнения comp
.Original:
Finds the smallest element in the range
[first, last)
. The first version uses operator< to compare the values, the second version uses the given comparison function comp
.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Содержание |
[править] Параметры
first, last | - | вперед итераторы определении диапазона для изучения
Original: forward iterators defining the range to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
cmp | - | comparison function which returns true if if *a is less than *b . The signature of the comparison function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. | |||||||||
Type requirements | |||||||||||
-ForwardIt must meet the requirements of ForwardIterator .
|
[править] Возвращаемое значение
Итератор для наименьшего элемента в диапазоне
[first, last)
. Если несколько элементов в диапазоне эквивалентных наименьший элемент, возвращает итератор на первый такой элемент. Возврат last
, если диапазон пуст.Original:
Iterator to the smallest element in the range
[first, last)
. If several elements in the range are equivalent to the smallest element, returns the iterator to the first such element. Returns last
if the range is empty.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[править] Сложность
Именно max(N-1,0) сравнений, где N = std::distance(first, last).
Original:
Exactly max(N-1,0) comparisons, where N = std::distance(first, last).
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[править] Возможная реализация
First version |
---|
template<class ForwardIt> ForwardIt min_element(ForwardIt first, ForwardIt last) { if (first == last) return last; ForwardIt smallest = first; ++first; for (; first != last; ++first) { if (*first < *smallest) { smallest = first; } } return smallest; } |
Second version |
template<class ForwardIt, class Compare> ForwardIt min_element(ForwardIt first, ForwardIt last, Compare comp) { if (first == last) return last; ForwardIt smallest = first; ++first; for (; first != last; ++first) { if (comp(*first, *smallest)) { smallest = first; } } return smallest; } |
[править] Пример
#include <algorithm> #include <iostream> #include <vector> int main() { std::vector<int> v{3, 1, 4, 1, 5, 9}; std::vector<int>::iterator result = std::min_element(v.begin(), v.end()); std::cout << "min element at: " << std::distance(v.begin(), result); }
Вывод:
min element at: 1
[править] См. также
возвращает наибольший элемент в диапазоне Original: returns the largest element in a range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) | |
(C++11) |
возвращает наименьший и наибольший элемент в диапазоне Original: returns the smallest and the largest element in a range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) |
Возвращает меньшее из двух элементов Original: returns the smaller of two elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) |