std::partition
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Заголовочный файл <algorithm>
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template< class BidirIt, class UnaryPredicate > BidirectionalIterator partition( BidirIt first, BidirIt last, |
(до C++11) (начиная с C++11) |
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[first, last)
таким образом, что все элементы, для которых предикат возвращает p
true предшествовать элементы, для которых предикат возвращает p
false. Относительный порядок элементов не сохраняются. [first, last)
in such a way that all elements for which the predicate p
returns true precede the elements for which predicate p
returns false. Relative order of the elements is not preserved. You can help to correct and verify the translation. Click here for instructions.
Содержание |
[править] Параметры
first, last | - | диапазон элементов в порядок
Original: the range of elements to reorder The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
p | - | unary predicate which returns true если элемент должны быть заказаны до других элементов . Original: if the element should be ordered before other elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. The signature of the predicate function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. | |||||||||
Type requirements | |||||||||||
-BidirIt must meet the requirements of BidirectionalIterator .
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-ForwardIt must meet the requirements of ValueSwappable and ForwardIterator . However, the operation is more efficient if ForwardIt also satisfies the requirements of BidirectionalIterator
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[править] Возвращаемое значение
You can help to correct and verify the translation. Click here for instructions.
[править] Сложность
ForwardIt
отвечает требованиям BidirectionalIterator
на наиболее своп (last-first)/2 сделали.ForwardIt
meets the requirements of BidirectionalIterator
at most (last-first)/2 swaps are done.You can help to correct and verify the translation. Click here for instructions.
[править] Возможная реализация
template<class BidirIt, class UnaryPredicate> BidirIt partition(BidirIt first, BidirIt last, UnaryPredicate p) { while (1) { while ((first != last) && p(*first)) { ++first; } if (first == last--) break; while ((first != last) && !p(*last)) { --last; } if (first == last) break; std::swap(*first++, *last); } return first; } |
[править] Пример
#include <algorithm> #include <functional> #include <iostream> #include <iterator> #include <vector> bool is_even(int i) { return i % 2 == 0; } int main() { std::vector<int> v; for (int i = 0; i < 10; ++i) v.push_back(i); std::cout << "Original vector:\n "; std::copy(v.begin(), v.end(), std::ostream_iterator<int>(std::cout, " ")); // Partition the vector std::vector<int>::iterator p = std::partition(v.begin(), v.end(), std::ptr_fun(is_even)); std::cout << "\nPartitioned vector:\n "; std::copy(v.begin(), v.end(), std::ostream_iterator<int>(std::cout, " ")); std::cout << "\nBefore partition:\n "; std::copy(v.begin(), p, std::ostream_iterator<int>(std::cout, " ")); std::cout << "\nAfter partition:\n "; std::copy(p, v.end(), std::ostream_iterator<int>(std::cout, " ")); }
Возможный вывод:
Original vector: 0 1 2 3 4 5 6 7 8 9 Partitioned vector: 0 8 2 6 4 5 3 7 1 9 Before partition: 0 8 2 6 4 After partition: 5 3 7 1 9
[править] См. также
(C++11) |
определяет, является ли диапазон разбивается данный предикат Original: determines if the range is partitioned by the given predicate The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) |
разделяет элементы на две группы, сохраняя их относительный порядок Original: divides elements into two groups while preserving their relative order The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) |