std::remove_copy, std::remove_copy_if
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Заголовочный файл <algorithm>
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template< class InputIt, class OutputIt, class T > OutputIt remove_copy( InputIt first, InputIt last, OutputIt d_first, |
(1) | |
template< class InputIt, class OutputIt, class UnaryPredicate > OutputIt remove_copy_if( InputIt first, InputIt last, OutputIt d_first, |
(2) | |
Copies elements from the range [first, last)
, to another range beginning at d_first
, omitting the elements which satisfy specific criteria. The first version ignores the elements that are equal to value
, the second version ignores the elements for which predicate p
returns true. Source and destination ranges cannot overlap.
Содержание |
[править] Параметры
first, last | - | диапазон элементов для копирования
Original: the range of elements to copy The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
d_first | - | the beginning of the destination range. |
value | - | the value of the elements not to copy |
Type requirements | ||
-InputIt must meet the requirements of InputIterator .
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-OutputIt must meet the requirements of OutputIterator .
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[править] Возвращаемое значение
You can help to correct and verify the translation. Click here for instructions.
[править] Сложность
last - first
применения предикатов.last - first
applications of the predicate.You can help to correct and verify the translation. Click here for instructions.
[править] Возможная реализация
First version |
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template<class InputIt, class OutputIt, class T> OutputIt remove_copy(InputIt first, InputIt last, OutputIt d_first, const T& value) { for (; first != last; ++first) { if (!(*first == value)) { *d_first++ = *first; } } return d_first; } |
Second version |
template<class InputIt, class OutputIt, class UnaryPredicate> OutputIt remove_copy_if(InputIt first, InputIt last, OutputIt d_first, UnaryPredicate p) { for (; first != last; ++first) { if (!p(*first)) { *d_first++ = *first; } } return d_first; } |
[править] Пример
The following code outputs a string while erasing the spaces on the fly.
#include <algorithm> #include <iterator> #include <string> #include <iostream> int main() { std::string str = "Text with some spaces"; std::cout << "before: " << str << "\n"; std::cout << "after: "; std::remove_copy(str.begin(), str.end(), std::ostream_iterator<char>(std::cout), ' '); std::cout << '\n'; }
Вывод:
before: Text with some spaces after: Textwithsomespaces
[править] См. также
удаляет элементы, удовлетворяющие определенным критериям Original: removes elements satisfying specific criteria The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (шаблон функции) |