std::pow

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Defined in header <cmath>
float       pow( float base, float exp );
(1)
double      pow( double base, double exp );
(2)
long double pow( long double base, long double exp );
(3)
Promoted    pow( Arithmetic base, Arithmetic exp );
(4) (C++11 起)
float       pow( float base, int iexp );
(5) (至 C++11)
double      pow( double base, int iexp );
(6) (至 C++11)
long double pow( long double base, int iexp );
(7) (至 C++11)
base次方计算值expiexp.
Original:
Computes the value of base raised to the power exp or iexp.
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4)
过载或一组函数模板的所有组合的算术类型的参数不包括1-3)。如果任何参数是整数类型,它被转换为double。如果任何参数是long double,则返回类型Promotedlong double,否则,返回类型总是double.
Original:
A set of overloads or a function template for all combinations of arguments of arithmetic type not covered by 1-3). If any argument has integral type, it is cast to double. If any argument is long double, then the return type Promoted is also long double, otherwise the return type is always double.
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目录

[编辑] 参数

base -
浮点值的基础
Original:
base as floating point value
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exp -
指数浮点值
Original:
exponent as floating point value
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iexp -
指数为整数值
Original:
exponent as integer value
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[编辑] 返回值

base提出的功率(expiexp
Original:
base raised by power (exp or iexp).
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域错误当base是0和exp是小于或等于0NAN是在这种情况下,返回.
Original:
Domain error occurs if base is 0 and exp is less than or equal to 0. NAN is returned in that case.
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域发生错误,如果base是负的且exp不是一个整数的值。 NAN是在这种情况下,返回.
Original:
Domain error occurs if base is negative and exp is not an integer value. NAN is returned in that case.
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范围错误发生,如果发生溢出。 HUGEVAL是在这种情况下,返回.
Original:
Range error occurs if an overflow takes place. HUGEVAL is returned in that case.
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[编辑] 注释

pow(float, int)回报float,直到C + +11(过载),但返回double因为C + +11(过载)
Original:
pow(float, int) returns float until C++11 (per overload 5) but returns double since C++11 (per overload 4)
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[编辑] 另请参阅

返回“E”提出的功率(ex
Original:
returns e raised to the given power (ex)
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(函数) [edit]
计算自然(基地“E”)对数(基地“E”)(ln(x)
Original:
computes natural (base e) logarithm (to base e) (ln(x))
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(函数) [edit]
计算平方根(x
Original:
computes square root (x)
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(函数) [edit]
(C++11)
计算立方米的根(3x
Original:
computes cubic root (3x)
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(函数) [edit]
复杂的电源,一个或这两个参数可以是复数
Original:
complex power, one or both arguments may be a complex number
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(函数模板) [edit]
适用的功能std::pow两个valarrays或valarray的和一个值
Original:
applies the function std::pow to two valarrays or a valarray and a value
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(函数模板) [edit]