up vote 1 down vote favorite

whats wrong with this picture?

$appleVar = 'apple';
$veggie = 'carrots';

$var = array('fruit' => $appleVar, 'veggie' => ''.$carrotVar.' no carrots please');

print_r($var);

when I print the array only "no carrots please" is displayed. why?

I'm so sorry I meant

$carrotVar = 'carrots'; not $veggie = 'carrots';
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1  
where does $carrotVar come from? or should that be $veggie – bumperbox Apr 13 '11 at 11:08

5 Answers

up vote 1 down vote accepted

When declaring the array, you are using $carrotVar :

$var = array(
    'fruit' => $appleVar, 
    'veggie' => ''.$carrotVar.' no carrots please'
);

But that $carrotVar variable is not defined.


You should probably use the $veggie variable :

$var = array(
    'fruit' => $appleVar, 
    'veggie' => ''.$veggie.' no carrots please'
);


Or rename it so it matches its content :

$carrotVar = 'carrots';
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up vote 2 down vote

change

$veggie = 'carrots';

to

$carrotVar = 'carrots';
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up vote 1 down vote

Have you checked carefully.

In my case it is printing :-

Notice: Undefined variable: carrotVar in /home/jatin/webroot/vcms/trunk/application/modules/ibroadcast/controllers/VideoController.php on line 10 Array (
    [fruit] => apple
    [veggie] =>  no carrots please )
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Since there is no carrotVar defined it is throwing notice also – Jatin Dhoot Apr 13 '11 at 11:09
up vote 0 down vote

You did not define $carrotVar.

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up vote 0 down vote

$appleVar = 'apple';
$veggie = 'carrots';
$carrotVar = $veggie . ' no carrots please';
$var = array('fruit' => $appleVar, 'veggie' => $carrotVar);

Or whatever your output needs to be?

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