std::lexicographical_compare
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Заголовочный файл <algorithm>
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template< class InputIt1, class InputIt2 > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, |
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template< class InputIt1, class InputIt2, class Compare > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, |
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comp
.comp
.You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
- Два диапазонов по сравнению элемент за элементом.Original:Two ranges are compared element by element.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Первый элемент несовпадение определяет, какой диапазон является лексикографически меньше' или' больше, чем другие.Original:The first mismatching element defines which range is lexicographically less or greater than the other.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Если диапазон является префиксом другой, более короткий диапазон лексикографически меньше', чем другие.Original:If one range is a prefix of another, the shorter range is lexicographically less than the other.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Если два диапазона имеют эквивалентные элементы и той же длины, то диапазоны лексикографически' равны.Original:If two ranges have equivalent elements and are of the same length, then the ranges are lexicographically equal.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Пустой диапазон лексикографически меньше', чем любая непустая диапазон.Original:An empty range is lexicographically less than any non-empty range.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - Два пустых диапазонах лексикографически' равны.Original:Two empty ranges are lexicographically equal.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
Содержание |
[править] Параметры
first1, last1 | - | первый ряд элементов для изучения
Original: the first range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
first2, last2 | - | второй ряд элементов для изучения
Original: the second range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. | |||||||||
Type requirements | |||||||||||
-InputIt1, InputIt2 must meet the requirements of InputIterator .
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[править] Возвращаемое значение
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[править] Сложность
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[править] Возможная реализация
First version |
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template<class InputIt1, class InputIt2> bool lexicographical_compare(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2) { for ( ; (first1 != last1) && (first2 != last2); first1++, first2++ ) { if (*first1 < *first2) return true; if (*first2 < *first1) return false; } return (first1 == last1) && (first2 != last2); } |
Second version |
template<class InputIt1, class InputIt2, class Compare> bool lexicographical_compare(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, Compare comp) { for ( ; (first1 != last1) && (first2 != last2); first1++, first2++ ) { if (comp(*first1, *first2)) return true; if (comp(*first2, *first1)) return false; } return (first1 == last1) && (first2 != last2); } |
[править] Пример
#include <algorithm> #include <iostream> #include <vector> #include <cstdlib> #include <ctime> int main() { std::vector<char> v1 {'a', 'b', 'c', 'd'}; std::vector<char> v2 {'a', 'b', 'c', 'd'}; std::srand(std::time(0)); while (!std::lexicographical_compare(v1.begin(), v1.end(), v2.begin(), v2.end())) { for (auto c : v1) std::cout << c << ' '; std::cout << ">= "; for (auto c : v2) std::cout << c << ' '; std::cout << '\n'; std::random_shuffle(v1.begin(), v1.end()); std::random_shuffle(v2.begin(), v2.end()); } for (auto c : v1) std::cout << c << ' '; std::cout << "< "; for (auto c : v2) std::cout << c << ' '; std::cout << '\n'; }
Возможный вывод:
a b c d >= a b c d d a b c >= c b d a b d a c >= a d c b a c d b < c d a b