std::copy, std::copy_if

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算法库
功能
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Functions
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修改序列操作
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Non-modifying sequence operations
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all_of
any_of
none_of
(C++11)
(C++11)
(C++11)
for_each
count
count_if
mismatch
equal
修改序列操作
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Modifying sequence operations
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分区操作
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Partitioning operations
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is_partitioned(C++11)
partition
partition_copy(C++11)
排序操作(排序的区间)
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Sorting operations (on sorted ranges)
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is_sorted(C++11)
is_sorted_until(C++11)
sort
二进制搜索操作(排序的区间)
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Binary search operations (on sorted ranges)
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设置操作(排序的区间)
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Set operations (on sorted ranges)
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堆的操作
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Heap operations
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最小/最大操作
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Minimum/maximum operations
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数字操作
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Numeric operations
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C库
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C library
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Defined in header <algorithm>
template< class InputIt, class OutputIt >
OutputIt copy( InputIt first, InputIt last, OutputIt d_first );
(1)
template< class InputIt, class OutputIt, class UnaryPredicate >

OutputIt copy_if( InputIt first, InputIt last,
                  OutputIt d_first,

                  UnaryPredicate pred );
(2) (C++11 起)
复制中的元素定义的范围内,由[first, last)到另一个范围开始于d_first。第二个功能只有谓词的元素复制pred回报true.
Original:
Copies the elements in the range, defined by [first, last), to another range beginning at d_first. The second function only copies the elements for which the predicate pred returns true.
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目录

[编辑] 参数

first, last -
元素的范围内,要复制的复本
Original:
the range of elements to copy
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d_first -
的目标范围的开头。如果d_first[first, last)std::copy_backward必须使用代替std::copy.
Original:
the beginning of the destination range. If d_first is within [first, last), std::copy_backward must be used instead of std::copy.
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pred - unary predicate which returns ​true
所需的元素
Original:
for the required elements
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.

The signature of the predicate function should be equivalent to the following:

bool pred(const Type &a);

The signature does not need to have const &, but the function must not modify the objects passed to it.
The type Type must be such that an object of type InputIt can be dereferenced and then implicitly converted to Type. ​

Type requirements
-
InputIt must meet the requirements of InputIterator.
-
OutputIt must meet the requirements of OutputIterator.

[编辑] 返回值

输出迭代器在目标范围内的元素,复制过去的最后一个元素.
Original:
Output iterator to the element in the destination range, one past the last element copied.
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[编辑] 复杂性

1)
究竟last - first任务
Original:
Exactly last - first assignments
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2)
究竟last - first的谓词中的应用
Original:
Exactly last - first applications of the predicate
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[编辑] 注释

在实践中,实现std::copy避免多次分配和使用大容量复制功能,如std::memcpy如果该值类型是TriviallyCopyable
Original:
In practice, implementations of std::copy avoid multiple assignments and use bulk copy functions such as std::memcpy if the value type is TriviallyCopyable
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[编辑] 可能的实现

First version
template<class InputIt, class OutputIt>
OutputIt copy(InputIt first, InputIt last, 
              OutputIt d_first)
{
    while (first != last) {
        *d_first++ = *first++;
    }
    return d_first;
}
Second version
template<class InputIt, class OutputIt, class UnaryPredicate>
OutputIt copy_if(InputIt first, InputIt last, 
                 OutputIt d_first, UnaryPredicate pred)
{
    while (first != last) {
        if(pred(*first))
            *d_first++ = *first;
         first++;
    }
    return d_first;
}

[编辑] 为例

下面的代码复制到一个向量和显示的内容都复制得到的载体
Original:
The following code uses copy to both copy the contents of one vector to another and to display the resulting vector:
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#include <algorithm>
#include <iostream>
#include <vector>
#include <iterator>
 
int main()
{
    std::vector<int> from_vector;
    for (int i = 0; i < 10; i++) {
        from_vector.push_back(i);
    }
 
    std::vector<int> to_vector(10);
 
    std::copy(from_vector.begin(), from_vector.end(), to_vector.begin());
 
    std::cout << "to_vector contains: ";
    std::copy(to_vector.begin(), to_vector.end(), 
              std::ostream_iterator<int>(std::cout, " "));
    std::cout << std::endl;
}

Output:

to_vector contains: 0 1 2 3 4 5 6 7 8 9

[编辑] 另请参阅

份向后为了在一个范围内的元素
Original:
copies a range of elements in backwards order
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(函数模板) [edit]
复制一个范围内的元素省略了那些满足特定的条件
Original:
copies a range of elements omitting those that satisfy specific criteria
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(函数模板) [edit]