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up vote 0 down vote favorite

i have the same json string twice but the second time i get an error.

{"data":[{"ServerID":"1","UserID":"3","Name":"salzig","State_since":"2012-11-23T23:16:27.458000000","State":"saved","UUID":"Hardware   85f5d278-f6d6-49c2-87e7-c249d8002897"}],"error":[null,null,null]} devcontrol.js:8

{"data":[{"ServerID":"1","UserID":"3","Name":"salzig","State_since":"2012-11-23T23:16:27.458000000","State":"saved","UUID":"Hardware   85f5d278-f6d6-49c2-87e7-c249d8002897"}],"error":[null,null,null]} devcontrol.js:8

Uncaught TypeError: Object function (E,F)} has no method 'parseJSON' devcontrol.js:9

my code line devcontrol.js 8 and 9:

console.log(data);
data = $.parseJSON(data);

how can that be.

update i now made a console.log($) evry trime bevor he trys to convert the string into a json and got 

undefined

it turnd out the secounde time it's undefined. i managed to found out it was because of zfdebug they used document ready and then asked about jquery noconfilect thats why $ was undifend the secound time

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1  
Are you using any other libraries that use $ as a variable? What happens when you try jQuery.parseJSON(data); –  Aesthete Nov 24 '12 at 2:04
    
show more code where the json comes from. Is data an object or a string? –  charlietfl Nov 24 '12 at 2:06
    
@charlietfl - What's the difference? –  Aesthete Nov 24 '12 at 2:07
    
You're going to need to give more information about what's going on in your code, because obviously there isn't just a bug in jQuery where it can't parse that string twice. –  Chris Martin Nov 24 '12 at 2:07
    
@Aesthete read the docs. Description: Takes a well-formed JSON string and returns the resulting JavaScript object. api.jquery.com/jQuery.parseJSON –  charlietfl Nov 24 '12 at 2:09
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1 Answer

up vote 2 down vote accepted 
Uncaught TypeError: Object function (E,F)} has no method 'parseJSON' devcontrol.js:9

Is telling you that the object you're referencing with the $ variable has no method called that. This could be caused by a few things.

  • You're using an old version that doesn't support this function. parseJSON was introduced in version 1.4.1. Either update your version, or use the native JSON.parse() method.
  • Your script link to jQuery is wrong. Checked the page loaded the source script with a 200 success
  • Another library is taking the $ variable after jquery has defined it. You can disassociate jQuery from the $ variable using jQuery.noConflict(), reassign to anothe variable like $$, or just using jQuery.parseJSON()
  • You have scripts running before the page is fully loaded. Make sure every is run within $(document).ready(function () { /*your code here*/ });
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1  
also make sure jQuery loaded before any jQuery dependent code –  charlietfl Nov 24 '12 at 2:42
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