up vote 2 down vote favorite
1

This is probably a fairly simple way to do it, but I ask since I did not find it on google.

What I want is to add an array under another.

var array = [];

array[0]["username"] = "Eric";
array[0]["album"] = "1";

Something like this, I get no errors in Firebug, it does not work. So my question is, how does one do this in javascript?

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you should NOT use array as variable name since it can be confused with the Array object. – Boris Guéry Dec 11 '09 at 9:31
Javascript IS case sensitive. – Vincent Robert Dec 11 '09 at 9:36
it is, but well, it wasn't an answer, rather an advice. – Boris Guéry Dec 11 '09 at 9:40
I only use "array" as a variable name, in this example here =) – sv88erik Dec 11 '09 at 9:40

4 Answers

up vote 7 down vote accepted 
var a= [
 { username: 'eric', album: '1'},
 { username: 'bill', album: '3'}
];
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thx a lot! men vist du da ønsker å legge til flere i arrayet i ettertid da? I mitt tilfellet er det en loop – sv88erik Dec 11 '09 at 9:36
1  
I'm so sorry, was so happy for your reply, I wrote it in my language. What I would say is: thx a lot! but shown when you want to add more in the array later then? In my case it is a loop – sv88erik Dec 11 '09 at 9:38
1  
var a = []; a.push({username: "foo", album: "3"}) – roryf Dec 11 '09 at 15:48
This is an array that contains objects. He wants an array that contains arrays. – Andrew Koper Dec 21 '12 at 17:16
up vote 1 down vote

try something like this 

array[0] = new Array(2);
array[1] = new Array(5);

More about 2D array here

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up vote 0 down vote

You should get an error in Firebug saying that array[0] is undefined (at least, I do).

Using string as keys is only possible with hash tables (a.k.a. objects) in Javascript.

Try this:

var array = [];
array[0] = {};
array[0]["username"] = "Eric";
array[0]["album"] = "1";

or 

var array = [];
array[0] = {};
array[0].username = "Eric";
array[0].album = "1";

or simpler

var array = [];
array[0] = { username: "Eric", album: "1" };

or event simpler

var array = [{ username: "Eric", album: "1" }];
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up vote 0 down vote

Decompose.

var foo = new Array();
foo[0] = {};
foo[0]['username'] = 'Eric';
foo[0]['album'] = '1';
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