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I have Javascript array which contains User object. I have created this array from modelAttribute. 

var userList = '${userList}';     // userList is a spring model attribute

userList contains list of User objects. I am accessing it as 

for(i=0;i<userList.length;i++)
    {
        if(searchKey == "" || userList[i].indexOf(searchKey) != -1)
        {   
            $('#userTable').dataTable().fnAddData( [
                  userList[i].firstName,
                  userList[i].lastName,
                  userList[i].institution,
                  userList[i].email] );
        }   
    }

But I am getting values as undefined. Initially I used Ajax call for same and it worked fine . 

$.getJSON("lookup/users", {name:searchKey,userType:"requester"}, function(userList) {
// It works fine        
        for(i=0;i<userList.length;i++)
        {
            $('#userTable').dataTable().fnAddData( [
                  userList[i].firstName,
                  userList[i].lastName,
                  userList[i].institution,
                  userList[i].email] );
        }

    });

How can I access it now ?

EDIT:
console.log("userList :" + userList); gives 

userList : [org.test.dto.UserDTO@11d1c59, org.test.dto.UserDTO@302f39, org.test.dto.UserDTO@16c57b1]
share|improve this question
try console.log(userList) to see what it actually contains – haynar Dec 13 '11 at 6:38
yes, try finding out the exact structure of the variable userList after you populate it. The structure could be different from what you think it is. Use console.log or put a break point in firebug after the assignment and check your watch block) or simply type userList in firebug console. – techfoobar Dec 13 '11 at 6:47
@haynar: Please check my edit. – Karna Dec 13 '11 at 6:48
@VijayakrishnanK: i checked it contains object. Please check my edit. – Karna Dec 13 '11 at 6:49
1  
what does "typeof userList" give? If it gives you a string, you will not be able to read it out as an array. In this case, you'll need to change the way data is being fed (a good way will be emulate how your AJAX handler lookup/users returns the data in JSON form). – techfoobar Dec 13 '11 at 7:16

4 Answers

up vote 2 down vote 
var userList = '${userList}';

userList is not an array.

Take out the quotes if it's supposed to render a javascript array.

share|improve this answer
I tried removing quotes. It gave me error Error: missing ] after element list Source File: http://localhost:7009/portal/request/form/add Line: 1006, Column: 56 Source Code: var userList = [org.test.dto.UserDTO@3c96a9, ..... – Karna Dec 13 '11 at 6:58
@YetAnotherCoder - if that's the actual source, I don't think that's even valid javascript. I get an error if I try to use @ anywhere. It looks to me like you need to serialize your data from whatever framework you're using to generate this list. org.test.dto.UserDTO@11d1cd59 may be an object in your framework, but it's just an undefined / illegal name in javascript. Take a look at what the server responded in your getJSON function - you'll see properly serialized JSON you can use as a template. – Yuji 'Tomita' Tomita Dec 13 '11 at 7:12
That might be the cause. I am using spring framework. Is there any other simple alternative to this ? – Karna Dec 13 '11 at 7:20
@YetAnotherCode - I'm not familiar with spring so you might want to ask a new question. You'd just need to pull the 4 attributes out you're trying to get: firstName, lastName, etc. and put those values into the array somehow. Where that happens in spring, I can't say... – Yuji 'Tomita' Tomita Dec 13 '11 at 8:03
Thanks buddy :) – Karna Dec 13 '11 at 8:34
up vote 1 down vote

Your if condition should probably be:

if(searchKey == "" || userList[i].firstName.indexOf(searchKey) != -1 || userList[i].lastName.indexOf(searchKey) != -1) {
    ...
}
share|improve this answer
Thanks for suggestion. – Karna Dec 13 '11 at 7:09
up vote 0 down vote

I see an error in your code. for(i=0; i < users.length;i++) is it works?

share|improve this answer
Yes. Can you please elaborate it ? – Karna Dec 13 '11 at 6:43
if $.getJSON return userList is right, and users are same as userList. may be the error is this for(i=0; i< users.length; i++) => for(var i = 0; i < users.length; i++) – blade Dec 13 '11 at 6:54
:its typo. I have updated it.Thanks. – Karna Dec 13 '11 at 7:00
up vote 0 down vote accepted

Used Ajax and Json for same and stored result in JS variable

userList = null; 
    $.getJSON("lookup/users", {name:"",userType:"requester"}, function(users) {
             userList = users;
         });
share|improve this answer

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