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1

Say I get this line of JSON

[{u'status': u'active', u'due_date': None, u'group': u'later', u'task_id': 73286}]

How can I convert those separate values to strings? So I can say

Print Status

And it returns

active
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3 Answers

up vote 4 down vote accepted

That is NOT a "line of JSON" as received from an external source. It looks like the result of json.loads(external_JSON_string). Also Print Status won't work; you mean print status.

>>> result = [{u'status': u'active', u'due_date': None, u'group': u'later', u'task_id': 73286}]
>>> print result[0]['status']
active

This is what a "line of JSON" looks like:

>>> import json
>>> json.dumps(result)
'[{"status": "active", "due_date": null, "group": "later", "task_id": 73286}]'
>>>

EDIT: If using Python 2.5, use import simplejson as json instead of import json. Make your code a bit more future-proof by doing this:

try:
    import json
except ImportError:
    import simplejson as json
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up vote 1 down vote

First of all, that ain't JSON as was already pointed out - it's python already.

I think you want the keys of the dict automatically transform into local variables. This would be a really bad idea, although in theory, it's possible using locals ():

result = [{u'status': u'active', u'due_date': None, u'group': u'later', u'task_id': 73286}]
for k, v in result[0].items():
    locals() [k] = v
print status # prints active

Some problems:

  • Your keys might overwrite some existing local variables
  • Keys might be unicode, how would you access the variable names?

Also, as stated in the python docs, locals () should not be modified.

In short: do it like this:

print result[0]['status']
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up vote 0 down vote 
import simplejson
_dict = simplejson.loads(json_data)
for entry in _dict:
# loop over list
    print entry.get('status','Failure')
    # Find key in dict/entry
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I get this error: File "/Library/Python/2.5/site-packages/simplejson/__init__.py", line 385, in loads return _default_decoder.decode(s) File "/Library/Python/2.5/site-packages/simplejson/decoder.py", line 402, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) TypeError: expected string or buffer – JCBK Apr 10 '11 at 21:06
-1 The "json_data" is the RESULT of [simple]json.loads – John Machin Apr 10 '11 at 22:40

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