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up vote -4 down vote favorite

Outline how a Java program could convert a string such as “1,2,3,4,5” into an array ({1, 2, 3, 4,5})

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What have you tried? –  Evan Knowles Mar 7 '13 at 12:32
 
Check this link: answers.yahoo.com/question/index?qid=20090824115249AAXkde1 –  Sarang Mar 7 '13 at 12:38
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4 Answers

up vote 0 down vote accepted

From zvzdhk:

String[] array = "1,2,3,4,5".split(",");

Then, parse your integers:

int[] ints = new int[arrays.length];
for(int i=0; i<array.length; i++)
{
    try{
        ints[i] = Integer.parseInt(array[i]);
    }
    catch(NumberFormatException nfe){
        //Not an integer, do some
    }
}
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It work for me thank you for your response but how does the .split(",") work ? –  Gorakh_sth Mar 7 '13 at 12:49
1  
Consult the Java API, it's a String method. docs.oracle.com/javase/6/docs/api/java/lang/… –  Ph4g3 Mar 7 '13 at 12:51
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up vote 1 down vote

Use StringTokenizer which will split string by comma and then put those values/tokens in array of integers.

StringTokenizer st = new StringTokenizer("1,2,3,4,5", ",");

int[] intArr = new int[st.countTokens()];
int i = 0;
while (st.hasMoreElements()) {
    intArr[i] = Integer.parstInt(st.nextElement());
    i++
}
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thank you so much –  Gorakh_sth Mar 7 '13 at 12:50
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up vote 1 down vote

Try this:

String[] array = "1,2,3,4,5".split(",");
int[] result = new result[array.length];
for (int i = 0; i < array.length; i++) {
    try {
         result[i] = Integer.parseInt(array[i]);
    } catch (NumberFormatException nfe) {};
}
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He need an Integer Array. –  Kugathasan Abimaran Mar 7 '13 at 12:33
 
thank you for your response .. –  Gorakh_sth Mar 7 '13 at 12:49
 
@Gorakh_sth you're welcome. –  zvdh Mar 7 '13 at 19:20
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up vote 0 down vote 
String [] str = "1,2,3,4,5".split(",");
int arrayInt[] = new int[str.length];
for (int i = 0; i < str.length; i++) 
    arrayInt[i]=Integer.valueOf(str[i]);
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