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up vote 1 down vote favorite

It's possible that I'm not properly using jQuery's inArray() function, but I have to construct an object that only has the indexes of two other JavaScript objects where the values match exactly:

var arr1 = {
    a: "alfa",
    b: "beta"};
var arr2 = {b: "beta"};
alert(jQuery.inArray(arr2, arr1));

Here, I expect to get an object that contains only:

{b: "beta"}

Similarly, if the arrays looked like this:

var arr1 = {
    a: "alfa",
    b: "beta",
    c: "test"};
var arr2 = {b: "beta",
            c: "not the same value"};

I would still expect:

{b: "beta"}

Because the values in the c index are not exactly the same.

Thanks in advance, ciao h.

share|improve this question
    
I've edited your question a bit to better reflect what you were asking. In the future, try to provide as much detail as you can when asking a question so that people can give you accurate, fast answers. :-) –  treeface Feb 18 '11 at 20:28
    
ok thank you for editing treeface –  haltman Feb 18 '11 at 22:06
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4 Answers

up vote 2 down vote accepted

Try this:

http://jsfiddle.net/treeface/u5xDz/1/

The idea here is that you loop over the arr1 object and see if a similar index exists in arr2, and if that index's value in arr1 matches that index's value in arr2.

var arr1 = {
        a: "alfa",
        b: "beta"
    },
    arr2 = {b: "beta"},
    combinedArr = {};


$.each(arr1, function(ind, el) {
    if (typeof arr2[ind] !== 'undefined' && arr1[ind] === arr2[ind])
        combinedArr[ind] = el;
});

console.log(combinedArr);
share|improve this answer
    
This is a good example of a custom comparison function. –  Neil Monroe Feb 18 '11 at 19:13
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up vote 1 down vote

The variables that you have defined in your example are not arrays, but objects. Also, the first parameter to this function should be the value to search for. So, your code would need to be modified to be:

var arr1 = [
    "alfa",
    "beta" ];
var arr2 = [ "beta" ];
alert(jQuery.inArray(arr2[0], arr1));

I think what you may be after is more of an intersect of two objects/arrays. You could use the jQuery.map() or jQuery.grep() functions to write a specialized comparison function.

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up vote 1 down vote

Default jQuery inArray function is not able to search in keys and values at the same time,

    $.fn.array_search = function(what, where)
    {
        var Match = null;
        if(where === undefined) var where = 'value';
        $(this).each(function(key, value)
        {
            if(where == 'value')
            {
                if(what == value) Match = key;
            }else
            {
                if(what == key) Match = value;  
            }
        });

        return (Match) ? Match : false;
    }

usage:

$(array).array_search('Value to Search'); //default search in value
$(array).array_search('key to search', 'key'); //search in key
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up vote 0 down vote

That is not an array. It is an object. Also [inArray][1] arguments are value, array. So you could check for an object in an array like this: 

var b = {b: "beta"}
var arr1 = [
    {a: "alfa"},
    b
];

alert(jQuery.inArray(b, arr1));

Arrays are declared with the square brackets 

[value,value]

Objects are declared 

{name: value, name: value }

[1]: http:// api.jquery.com/jQuery.inArray

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1  
This is not an answer. It is a comment. –  Richard Marskell - Drackir Feb 18 '11 at 19:03
    
@Drackir - I know, I got post happy. –  Josiah Ruddell Feb 18 '11 at 19:07
    
Thanks for fixing it. Add a link to this too for the OP: api.jquery.com/jQuery.inArray (I didn't -1 by the way.) –  Richard Marskell - Drackir Feb 18 '11 at 19:08
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