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up vote 0 down vote favorite

If I know that I'm only looping two times in a while loop, how do I switch array values after the first loop?

This is my array, $myarr:

Array ( // echo out array values from first loop
    [id1] => values_one
    [id2] => values_two
)

Array ( // echo out array values from second loop
    [id2] => values_two
    [id1] => values_one
)


$arr = array_values($myarr);
while($row = $query->fetch(PDO::FETCH_ASSOC))
{
 // ... more code
 //echo's out array values
   echo $arr[0]; //first loop should be values_one, second loop should be values_two
   echo $arr[1]; //first loop should be values_two, second loop should be values_one

}

Thank you

share|improve this question
    
A flag? ....... –  keyboardSmasher Dec 14 '12 at 4:38
    
A "for" loop?.. –  keyboardSmasher Dec 14 '12 at 4:39
    
I feel like there's something missing...code...or better explanation of question. –  bobthyasian Dec 14 '12 at 4:40
    
yeah, he's loading $row with an assoc array an then doesn't use it. Strange. –  keyboardSmasher Dec 14 '12 at 4:42

1 Answer 1

up vote 1 down vote accepted

With such a vague question, its difficult to be sure of 'edge cases'. But the below will solve your issue based upon what you have written above.

$arr = array_values($myarr);
while($row = $query->fetch(PDO::FETCH_ASSOC))
{
 // ... more code
 //echo's out array values
   echo $arr[0]; //first loop should be values_one, second loop should be values_two
   echo $arr[1]; //first loop should be values_two, second loop should be values_one
   $arr = array_reverse($arr, false);
}
share|improve this answer
    
exactly what i was looking for! Thank you! –  andrewliu Dec 14 '12 at 5:02

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