Tell me more ×
Unix & Linux Stack Exchange is a question and answer site for users of Linux, FreeBSD and other Un*x-like operating systems.. It's 100% free, no registration required.
up vote 2 down vote favorite
1

I have created this Function , which generate below output on terminal , but this function seems complex, So I posted here for any improvement or for same alternate solution. enter image description here

#!/bin/bash
function box_out() {
        input_char=$(echo "$@" | wc -c)
        line=$(for i in `seq 0 $input_char`; do printf "-"; done)
        # tput This should be the best option. what tput does is it will read the terminal info and render the correctly escaped ANSI code for you. code like \033[31m will break the readline library in some of the terminals.
        tput bold
        line="$(tput setaf 3)${line}"
        space=${line//-/ }
        echo " ${line}"
        printf '|' ; echo -n "$space" ; printf "%s\n" '|';
        printf '| ' ;tput setaf 4; echo -n "$@"; tput setaf 3 ; printf "%s\n" ' |';
        printf '|' ; echo -n "$space" ; printf "%s\n" '|';
        echo " ${line}"
        tput sgr 0
}

box_out $@
share|improve this question

1 Answer

up vote 4 down vote accepted

As your shebang and syntax indicates unportable bash, I prefer it this way:

function box_out()
{
  local s="$*"
  tput setaf 3
  echo " -${s//?/-}-
| ${s//?/ } |
| $(tput setaf 4)$s$(tput setaf 3) |
| ${s//?/ } |
 -${s//?/-}-"
  tput sgr 0
}

Of course, you can optimize it if you wish.

share|improve this answer
+1 I like the replace text with border. :) – peterph Mar 30 at 18:20
Awesome.............. You are Master .... – Rahul Patil Mar 31 at 8:29

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.