PHP Double Variable Array Issue

Question

I have a variable stack in object form:

• $people->one
• $people->two
• $people->three
• $people->four

I also have an array of data that when applicable, I want to replace those values. The array has things like: Lets call the array $stats

• "two" => 1
• "four" => 14

What I have been trying to accomplish (and this was using the double variable, is replace the value in the original object stack with an updated value if in the array.

foreach ($stats as $key => $value) {    
    $data = "people->" . $key;
    $$data = "<strong>" . $$data .  "</strong>";
}

But, that just doesn't look like it should work, and isn't as clean as I would like it. Is there a better way to handle something like this?

Thanks for any help that can be provide.

^^^

Update:

Basically I am trying to wrap around a variable, if the variable shows up in the array. And, then have it print like the original value, except with the wrapped around it.

Answer 1

foreach ($arrayvariable as $key => $val) {    
    $value->$key = "<strong>" . $value->$key .  "</strong>";
}

I suspect you meant

$$data = "<strong>" . $value .  "</strong>";

in your question, which would translate to

$value->$key = "<strong>" . $val .  "</strong>";

Answer 2

$value        = new stdClass();
$value->one   = 1;
$value->two   = 2;
$value->three = 3;
$value->four  = 4;

$arr          = array();
$arr['one']   = 11;
$arr['four']  = 14;

foreach($value as $key => &$val){
    if(isset($arr[$key])) {
        $val = $arr[$key];
    }
}

var_dump($value); // object(stdClass)#1 (4) { ["one"]=> int(11) ["two"]=> int(2) ["three"]=> int(3) ["four"]=> &int(14) }

Answer 3

If $obj is your object, you can do this.

$key = 'four';
echo $obj->$key;