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I have a mac address in this format 

00:45:36:45:f2:00

I want to convert this mac address into byte array. I mean, by removing the ':' in between, i get total of 6 bytes and those 6 bytes should sit as six bytes in a byte array. And how is that byte array converted into an integer? Is there any in-built function in python that would do that with very very less execution time(like in microseconds)? I have never come across these concepts before. Please shed some light on this. Thanks in advance

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1 Answer

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In Python 2.7,

macstr = addr.replace(':', '').decode('hex')

In Python 3, 

import binascii
macbytes = binascii.unhexlify(addr.replace(b':', b''))
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binascii works in python2 as well – jterrace yesterday
if i do in this way, total of 12 bytes are in byte array, not 6. in the mac address, f2 has to sit as 1 byte, not as 2 bytes in the byte array – Justin Carrey 13 hours ago
Works for me. Edit and post the code you're trying to use... – nneonneo 11 hours ago
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