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Hello People please find my code below as you can see iam trying to pass php array values to js function if i run this scipt i get 3 alerts parameter0=1,parameter1=2 and parameter2=3 differently...what iam trying to do is i need to save parameter0,parameter1 and parameter3 so that i can pass it one more function....please help me to do this.....

<script type="text/javascript">
function mufunc(a)
{
    var temp = new Array();
    dump(temp);
    temp = a.split('~');
    var parameter;
    for(i=0;i<temp.length;i++)
    {
        alert('parameter'+i+'='+temp[i]);               
    }
    //alert('sri'+i+'='+temp[i]);
}
</script>

<?php
$a = array('1','2','3');
$b = implode("~",$a);
?>
<a href="javascript:void(0)" onClick="mufunc('<?php echo $b; ?>')">Click Here</a>
share|improve this question
Why implode with a wacky delimiter? just do this <?php echo implode(',',$b);, and in your JS function: var parameters= Array.prototype.slice.apply(arguments,[0]);, and paramters will be an array, that looks like this: [1,2,3]. Job done – Elias Van Ootegem Nov 27 '12 at 17:23

6 Answers

up vote 0 down vote accepted

You can declare temp in the global scope, so that it can be used later in any scope:

var temp = new Array();

function mufunc(a)
{
    dump(temp);
    temp = a.split('~');
    var parameter;
    for(i=0;i<temp.length;i++)
    {
        alert('parameter'+i+'='+temp[i]);               
    }
    //alert('sri'+i+'='+temp[i]);
}

Alternatively:

var params = new Array();

function mufunc(a)
{
    var temp= new Array();
    dump(temp);
    temp = a.split('~');
    var parameter;
    for(i=0;i<temp.length;i++)
    {
        alert('parameter'+i+'='+temp[i]);   
        params['parameter'+i] = temp[i];          
    }
}

Now you can access it like:

alert( params['parameter0'] );
alert( params['parameter1'] );
share|improve this answer
thanks for your reply serverbloke but its not working ...var temp = new Array(); function mufunc(a) { dump(temp); temp = a.split('~'); var parameter; for(i=0;i<temp.length;i++) { alert('parameter'+i+'='+temp[i]); } alert(parameter0); } – Friend Nov 27 '12 at 17:17
See my edit if you want to access it like that... – ServerBloke Nov 27 '12 at 17:20
i got it thanks dear.. i have accepted your answer – Friend Nov 27 '12 at 17:56
up vote 1 down vote

do this

$b = json_encode($a);

and look for JSON on stackoverflow or Google for how to access it.

share|improve this answer
up vote 0 down vote

Its working as your code is writen.

Your counts are different, one starts at 0, one starts at 1:

Try changing your start variable in the for loop to 1 and then minus 1 off the i in temp, you should get:

parameter1=1,parameter2=2 and parameter3=3

share|improve this answer
up vote 0 down vote

Just use a global array variable, and assign parameters to that.

var parameter = [];
function mufunc(a)
{
var temp = new Array();
dump(temp);
temp = a.split('~');    
for(i=0;i<temp.length;i++)
{
    alert('parameter'+i+'='+temp[i]); 
    parameter[i] = temp[i];              
 }    
}
share|improve this answer
up vote 0 down vote

Take advantage of PHP's json_encode function on this one.

<script type="text/javascript">

function mufunc(a)
{
    // removed "var" to make "temp" global.
    // and we don't have to parse anything, the JS engine did
    // it for us already!
    temp = new Array();
    for(var i=0; i < temp.length; i++)
    {
        alert(i + ": " temp[i]); 
    }
}
</script>

<?php
$a = array('1','2','3');
$object_string = json_ecode($a);
?>
<a href="javascript:void(0)" onClick="mufunc(<?php print $object_string; ?>)">Click Here</a>
share|improve this answer
up vote 0 down vote

Since my comment could be considered an answer, I'll (re) post it here:

In your php script, just pass the arguments like so:

onclick="<?php echo implode(',',$b);?>">
//or if the you're dealing with strings:
onclick="<?php echo '"'.implode('","',$b).'"';?>">

And then do this in myfunc

function myfunc()
{
    var parameters = Array.prototype.slice.apply(arguments,[0]);
}

Arguments are available in all functions, and contain all data that was passed to that function as an argument, weather the function was defined with a certain number of arguments or not. Read all about it on MDN

The arguments object looks like an array, but isn't one, that's why -to slice it- you need to apply the slice method from the Array prototype. MDN - Apply for more info.

All in all, that's the quickest way to get to what you need, IMHO
BTW: Don't use the array constructor, use the array literal notation: []. The array constructor might behave a little odd from time to time

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