PHP - Select Array from List of Arrays in Foreach loop

Question

I have an array of arrays. Each array contains a user's information (name, email, username, etc). When a user is logged in, the page needs to display the arrays in a table. (This is working fine)

<table>

    <?php
        if(isset($_SESSION['logged_in_user'])) {
            echo '<tr>';
            for ($i = 0; $i < count($item_names); $i++) {
                if ($i == 8) continue;
                echo "<th scope=\"col\">$item_names[$i]</th>";
            }
            echo '</tr>';
            $altrow = false;
            foreach ($contacts as $contact) {
                echo ($altrow) ? '<tr class="alt">' : '<tr>';
                $altrow = !$altrow;
                for ($i = 0; $i < count($contact); $i++) {
                    if ($i == 8) continue;
                    echo "<td>$contact[$i]</td>";
                }
                echo '</tr>'; 
            }
        }
    ?> 
</table>

But I would also like the table to highlight the array(row) of the specific logged in user.

I have tried (and failed):

<table>
    <?php
        if(isset($_SESSION['logged_in_user'])) {
            echo '<tr>';
            for ($i = 0; $i < count($item_names); $i++) {
                if ($i == 8) continue;
                echo "<th scope=\"col\">$item_names[$i]</th>";
            }
            echo '</tr>'
            $altrow = false;
            foreach ($contacts as $contact) {
                if ($contact[1] == $_SESSION['logged_in_user']) {
                    echo '<tr class="highlight">' : '<tr>'; 
                } else {
                    echo ($altrow) ? '<tr class="alt">' : '<tr>';
                    $altrow = !$altrow;
                    for ($i = 0; $i < count($contact); $i++) {
                        if ($i == 8) continue;
                            echo "<td>$contact[$i]</td>";
                        }
                    }
                    echo '</tr>'; 
                }
            }
    ?> 
</table>

Am I not even close? Any help is appreciated!

Your indenting is confusing. The ending bracket should at least be at the same indentation as the beginning block. Not before it.
I'm going to attempt to indent your code properly. Note that proper indentation allows errors to be more easily spotted.

Santosh kumar · Answer 1 · 2012-11-01 05:02:21Z

up vote 0 down vote

hi yaar simply check tour loop foreach ($contacts as $contact=>$value) { //manipulate $value here and or you can check by printing $value here

}

answered Nov 1 '12 at 5:02

Santosh kumar
563

	This does not help the question. – Daedalus Nov 1 '12 at 5:03
	Hi can u post bit peace of array then i can explain u how to display if your array is like array([0]=>array('name'=>'john')) and if you apply foreach ($contacts as $contact=>$value) { $value['name'] give u value john....... } – Santosh kumar Nov 1 '12 at 5:05
	The array goes like: `$contacts = array ( array(1000, "Garrett", "Salinas", ... array(1001, "Xander", "Ryan", ... – BDV Nov 1 '12 at 5:30
	well as i get your array is like array ( array(1000, "Garrett", "Ryan"), array(1001, "Xander", "Ryan")....) You write foreach ($contacts as $_contact){ echo $_contact[0]; //this give u id} Hope it help! – Santosh kumar Nov 2 '12 at 11:13

Er. Anurag Jain · Answer 2 · 2012-11-01 05:24:37Z

Please try code given below

<table>
   <?php
    if(isset($_SESSION['logged_in_user'])) {
        echo '<tr>';
        for ($i = 0; $i < count($item_names); $i++) {
            if ($i == 8) continue;
                echo "<th scope=\"col\">$item_names[$i]</th>";
         }
        echo '</tr>';

      $altrow = false;

      foreach ($contacts as $contact) {
        if ($contact[1] == $_SESSION['logged_in_user']) {
            echo '<tr class="highlight">'; 
        } else {
            echo ($altrow) ? '<tr class="alt">' : '<tr>';
         }   
           $altrow = !$altrow;
            for ($i = 0; $i < count($contact); $i++) {
                if ($i == 8) continue;
                     echo "<td>$contact[$i]</td>";
             }

            echo '</tr>'; 
         }
      }
   ?> 
</table>

There was some bracket mistake in your code like } else {}.

I hope it will be working for you.

thanks

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active	6 months ago

PHP - Select Array from List of Arrays in Foreach loop

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