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I have a string in javascript like this:

frmSearch=FeeType=RecordingSpend:LoginID=:PersonCalled=:FeeAmount=22.234567:Paid=

I want to remove :FeeAmount=22.234567 part from this string using Regex or string.replace.

It can be empty like this:

frmSearch=FeeType=RecordingSpend:LoginID=:PersonCalled=:FeeAmount=:Paid=

or it can contain any value

I tried this:

var str= frmSearch.substr(frmSearch.indexOf(":FeeAmount"), frmSearch.indexOf(":Paid="));

How can I do it using regex?

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3  
What did you try? –  Prinzhorn Jun 2 '13 at 8:13
    
I have been trying substring and string.replace combination but they don't work –  DotnetSparrow Jun 2 '13 at 8:13
1  
@DotnetSparrow: Show the effort, so people can help you figure out where you went wrong (and so this doesn't look like a "please write this for me" question). –  T.J. Crowder Jun 2 '13 at 8:14
    
@T.J.Crowder - It should've worked with .substring() or .slice(), both of which take a start and end index, but .substr() takes a start and length. DotnetSparrow - is your desired output the original string minus that part (as assumed by the answers jcsanyi and I posted), or is the FeeAmount=... the part you want to keep? –  nnnnnn Jun 2 '13 at 9:50
    
@nnnnnn: Doh! :-) –  T.J. Crowder Jun 2 '13 at 10:06
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3 Answers

up vote 4 down vote accepted 
var frmSearch = "FeeType=RecordingSpend:LoginID=:PersonCalled=:FeeAmount=22.234567:Paid=";
frmSearch = frmSearch.replace(/(^|:)FeeAmount=[^:]*/,'$1FeeAmount=');

...will leave FeeAmount= in the string. To remove it completely:

frmSearch = frmSearch.replace(/(^|:)FeeAmount=[^:]*/,'');
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1  
My understanding is that the second example in the question is a second possible input, not the expected output. –  jcsanyi Jun 2 '13 at 8:16
    
@nnnnn what does it mean by (^|:) and [^:]* ? –  DotnetSparrow Jun 2 '13 at 8:20
1  
There's plenty of JS regex documentation available. –  nnnnnn Jun 2 '13 at 8:20
    
@DotnetSparrow: (^|:)FeeAmount = Match FeeAmount at the beginning of the string (^), or after a :. The [^:]* means "zero or more characters that are NOT :". –  T.J. Crowder Jun 2 '13 at 8:21
1  
@jcsanyi - Yes. It wasn't a problem when I thought the idea was to leave an "empty" FeeAmount= in the string, but I don't have time now to fix the second version. (I'm off to cook dinner.) –  nnnnnn Jun 2 '13 at 8:24
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up vote 2 down vote

How about this?

var input = 'frmSearch=FeeType=RecordingSpend:LoginID=:PersonCalled=:FeeAmount=22.234567:Paid=';
var output = input.replace(/:FeeAmount=[0-9.]*/, '');
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up vote 0 down vote

According to the question, the matching regex rule may be

':FeeAmount=[^:]*'
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