Frequency response is the quantitative measure of the output spectrum of a system or device in response to a stimulus, and is used to characterize the dynamics of the system.
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Digital control: Exercise solution
Can you help me (show me how) to solve the following exercise?
For the process with transfer function $G(s)=e^{-2s}/(s+1)$ design a digital controller with sampling time $T_{s} = 1$ that meets the ...
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Impulse Response Question
For the differential equation
$$\frac{d^2y(t)}{dt^2}+\frac{3dy(t)}{dt} + 2y = x(t),$$
I was able to find the frequency response as $$H(j\omega)= \frac{1}{-\omega^2+3j\omega+2}.$$ However, I am not ...
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1answer
76 views
Frequency response of Low pass filter and High pass filter
The transfer function of a Low pass filter is H(w). From this I want to develop a high Pass filter. I read in DSP by Proakis, Sec 4.5, that the high pass filter can be obtained by translating H(w) by ...
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1answer
75 views
Constant Magnitude Chirp across audio band (Parseval's Theorem?)
I want to excite a loudspeaker with a constant magnitude chirp that sweeps across all frequencies in the audio band. I downloaded a test file from this website to start with.
I plot the log magnitude ...
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1answer
40 views
Find the frequency response if i have the magnitude response?
if i have the transfer function of magnitude response is there a method that i could calculate the frequency response?
For example the transfer function of the magnitude response is:
$ 3db \pm ...
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1answer
80 views
Approximating the frequency response of a median filter
A median filter is a non-linear and lossy process, so it doesn't have a closed form frequency response as would a FIR filter (say a box filter of the same length) in an LTI system.
But how closely ...
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2answers
85 views
Why is the gain of my IIR filter positive?
Sorry, two questions in one day!
I'm struggling to understand what I'm doing wrong in this very simple filter design. I want to design a simple, single pole low pass filter and implement it as an IIR ...
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1answer
54 views
narrow band frequency response creation and general FR question
i need some guidance with understanding frequency response characteristics.
i have the a signal A with is played on speakers and recorded via microphone which is signal B.
then i apply a window ...
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2answers
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Obtaining the Impulse response from the frequency of a discrete system
I have the following discrete system's transfer function (Z domain):
$$h[z] = {z \over z - \frac{1}{2} }$$
I need to obtain the following:
The frequency response.
The impulse response.
The fourier ...
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0answers
121 views
Impulse Response / Frequency response Question
I have a major question. Please take a look.
I have this differential equation (DE):
$$
\frac{d^2y(t)}{dt} +\frac{dy(t)}{dt} +4y(t)= \frac{dx(t)}{dt} +2x(t)
$$
And I have to find impulse response ...
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votes
2answers
126 views
Find the frequency response of a system
I'm trying to find the frequency response $$H(\omega) = Y(\omega)/X(\omega)$$
for this system- the signal equations are given:
$$y[n] = v[n - M] - g * v[n]$$
$$v[n] = x[n] + g * v[n - M]$$
I've tried ...
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119 views
Evaluating loudspeakers
If you don't have a lot of money to spend but you want to estimate the frequency response of different loudspeaker setups what is the best way to do it?
I bought a very nice microphone and built a ...
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1answer
131 views
Calculating the system output using frequency response
Given an input signal $$x(n)=\cos(6\pi n +\frac{\pi}{6})$$ and system $$y(n)=0.5x(n)-0.1x(n-1)$$. In this case, the coefficients of the difference equation are $a_0=1$, $b_0=0.5$, and $b_1=$. The ...
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370 views
Plotting the magnitude response of a biquad filter
I've put together a multi-band audio EQ using biquad filters. I'm getting the coefficients using the methods from the RBJ cookbook.
http://www.musicdsp.org/files/Audio-EQ-Cookbook.txt
Now I want to ...
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1answer
232 views
Ultrasonic speaker calibration and emitting calibrated signals
I'm trying to calibrate an ultrasonic speaker with the aim of emitting predictable signals, but alas I keep running into trouble, probably due to my lack of DSP-fu.
A little background
I want to be ...