How should I make a string from a lazy sequence in clojure?

Question

I use str to construct strings all the time:

user> (str '(1 2 3) " == " '(1 2 3))
"(1 2 3) == (1 2 3)"

and roughly once a day I get bitten on the ass by:

user> (str '(1 2 3) " == " (map identity '(1 2 3)))
"(1 2 3) == clojure.lang.LazySeq@7861"

I guess I can say:

user> (with-out-str (print '(1 2 3) " == " (map identity '(1 2 3))))
"(1 2 3)  ==  (1 2 3)"

instead, but it seems ugly. Is there a better way?

Answer 1

You can use print-str:

(print-str '(1 2 3) " == " (map identity '(1 2 3)))
;; => "(1 2 3) == (1 2 3)"

Answer 2

You can turn a LazySeq object into a Cons one by using seq:

user=> (str '(1 2 3) " == " (map identity '(1 2 3)))
"(1 2 3) == clojure.lang.LazySeq@7861"

user=> (str '(1 2 3) " == " (seq (map identity '(1 2 3))))
"(1 2 3) == (1 2 3)"