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up vote 9 down vote favorite
2

Suppose that I have this partial view:

Your name is <strong>@firstName @lastName</strong>

which is accessible through a child only action like:

[ChildActionOnly]
public ActionResult FullName(string firstName, string lastName)
{

}

And I want to use this partial view inside another view with:

@Html.RenderPartial("FullName")

In other words, I want to be able to pass firstName ans lastName from view to partial view. How should I do that?

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Very closely related question: stackoverflow.com/questions/1909134/… – Chris Moschini Mar 18 at 23:17

3 Answers

up vote 16 down vote accepted

use this overload (docs):

public static void RenderPartial( this HtmlHelper htmlHelper, string partialViewName, Object model )

so:

@{Html.RenderPartial("FullName", new { firstName = model.FirstName, lastName = model.LastName});}

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1  
Well, tried that, but I'm getting The best overloaded method match for 'System.Web.WebPages.WebPageExecutingBase.Write(System.Web.WebPages.HelperResult‌​)' has some invalid arguments error. How should I implement the controller method? Should it have input parameters? – Saeed Neamati Jul 1 '11 at 15:06
The RenderPartial method returns void, as the views render directly into the output stream, not into a string. I edited my answer to fix this issue. – David Wick Jul 1 '11 at 16:07
did you add the {} around the call? it needs to be @{Html.RenderPartial("FullName", new { firstName = model.FirstName, lastName = model.LastName});} not @Html.RenderPartial("FullName", new { firstName = model.FirstName, lastName = model.LastName}); – BlackTigerX Jul 1 '11 at 16:18
@blacktigerx, yup. – David Wick Jul 1 '11 at 16:44
2  
You also don't need the brackets. @Html.Partial() is the same as @{Html.RenderPartial();} but much prettier. They have the same overloads as well. – smdrager Jun 21 '12 at 18:03
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up vote 5 down vote

You need to create a view model. Something like this should do...

public class FullNameViewModel()
{
     public string FirstName { get; set; }
     public string LastName { get; set; }

     public FullNameViewModel() { } 

     public FullNameViewModel(string firstName, string lastName)
     {
          this.FirstName = firstName;
          this.LastName = lastName;
     }

}

then from your action result pass the model

return View("FullName", new FullNameViewModel("John", "Doe");

and you will be able to access @Model.FirstName and @Model.LastName

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up vote 3 down vote

make sure you add {} around Html.RenderPartial, as:

@{Html.RenderPartial("FullName", new { firstName = model.FirstName, lastName = model.LastName});}

not

@Html.RenderPartial("FullName", new { firstName = model.FirstName, lastName = model.LastName});
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