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up vote 2 down vote favorite

If I want to pop the last item from my NSMutableArray would this be the most proper way?

id theObject = [myMutableArray objectAtIndex:myMutableArray.count-1];
[myMutableArray removeLastObject];

I'm sure someone from SOF has a better way.

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3 Answers

up vote 8 down vote accepted

Retain it, delete it, use it, release it.

id theObject = [[myMutableArray lastObject] retain];
[myMutableArray removeLastObject];
//use theObject....
[theObject release];
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up vote 6 down vote

There is no pop equivalent for NSMutableArray but I guess you could easily add a category to it for popping. Something like this perhaps:

NSMutableArray+Queue.h

@interface NSMutableArray (Queue)
-(id)pop;
@end

NSMutableArray+Queue.m

#import "NSMutableArray+Queue.h"

@implementation NSMutableArray (Queue)
-(id)pop{
    id obj = [[[self lastObject] retain] autorelease];
    [self removeLastObject];
    return obj;
}
@end

Then import it and use it like this:

#import "NSMutableArray+Queue.h"
...
id lastOne = [myArray pop];
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Are you sure you the object it returns should be copied? I would expect to pop the same object off the stack that I put on it. –  Monolo Jun 11 '12 at 19:49
    
@Monolo Thanx man I have updated the answer (if anyone knows though how this could be done under ARC I would be interested). –  Alladinian Jun 11 '12 at 19:58
    
Just get rid of the retain and autorelease messages. ARC should take care of the rest. –  Zev Eisenberg Jan 26 at 3:19
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up vote 1 down vote

You can use lastObject to get the last object in the array.

That would save you a few keystrokes.

If you want to be able to call it with a single line of code, you can wrap it all in a function or a category on NSMutableArray.

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