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My date string is like this dd.MM.yyyy-HH.mm.ss . I am doing following:

String s_date= ""13.06.2012-12.12.12"
Date d_date = new SimpleDateFormat("dd.MM.YYYY", Locale.ENGLISH).parse(s_date);

But it is throwing Unparseable date: "13.06.2012-12.12.12" Exception.

How can I make it work for the given date-time format ?

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That actually doesn't throw an exception for me - which surprises me, given that you haven't provided any time parts in your format string... – Jon Skeet 6 mins ago

3 Answers

up vote 1 down vote

You should add time as well:

 new SimpleDateFormat("dd.MM.YYYY-HH.mm.ss", Locale.ENGLISH)
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up vote 1 down vote

String s_date= "13.06.2012-12.12.12" doesn't fit your pattern dd.MM.YYYY. You should remove the part after the - if you want date without hours:

s_date = s_date.substring(0, s_date.indexOf('-'));

or change your pattern as Michał said.

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up vote 0 down vote

Change to this

String s_date= ""13.06.2012-12.12.12"
Date d_date = new SimpleDateFormat("dd.MM.YYYY-HH.mm.ss", Locale.ENGLISH).parse(s_date);
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