PHP Parse error: syntax error, [closed]

Question

I keep getting the following error when building an array:

PHP Parse error:  syntax error, unexpected ';', expecting ')'

for the following code:

$fetchResult=$PubMedClient->run_eFetch(array(
'db'=>'pubmed',
'id'=>(count($searchResult->IdList->Id)>1 ? join(",",$searchResult->IdList->Id) : $searchResult->IdList->Id)));

I've tried to break this up in many ways, but it does not work. As usual, I'm sure it is something simple that I'm just not seeing.

Anyone have an idea?

Many thanks

Another closing ) is required at the end. You've not closed your run_eFetch function — NoGall, Commented Jun 13, 2013 at 14:23
Do you want us to count your brackets? Use a decent IDE or count them yourself. — CodeCaster, Commented Jun 13, 2013 at 14:24

Gavin Anderegg · Accepted Answer · 2013-06-13 14:24:46Z

2

It would be slightly easier to read if you broke out the ternary operation into a variable like so:

$getID = count($searchResult->IdList->Id) > 1 ? join(",", $searchResult->IdList->Id) : $searchResult->IdList->Id;

$fetchResult = $PubMedClient->run_eFetch(
    array(
        'db'=>'pubmed',
        'id'=> $getID
    )
);

The above should work.

answered Jun 13, 2013 at 14:24

Gavin Anderegg

6,3872 gold badges28 silver badges36 bronze badges

Many thanks for the responses. I did close with the last bracket ")" before the semicolon, but that was not working either.
– Ken
Commented Jun 13, 2013 at 14:39

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