Python IEEE754 from bytearray

Question

I have a IEEE-754 number being sent to a Raspberry-Pi running Python3. Its sent as four serial bytes, but I can't figure out how to assemble this into a floating point number in Python.

Tried the various posts about using struct.pack but can't get this to give a sensible result?

Fairly new to Python, so it might be a easy answer?

This looks like a good question, although it might be helpful to include some code snippets as to what you've tried. — Hannele, Commented Jun 11, 2013 at 21:18

lynn · Accepted Answer · 2013-06-11 21:21:25Z

3

You want struct.unpack, not struct.pack:

struct.unpack('<f', bytes) # little-endian
struct.unpack('>f', bytes) # big-endian

edited Jun 11, 2013 at 21:21

answered Jun 11, 2013 at 21:03

lynn

10.9k48 silver badges81 bronze badges

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+1. But you probably want to make the endianness explicit. Of course you have to know what the endianness is. If the docs for the sender don't say, I'd try !f as a first guess, and if that gives me garbage, use <f.
– abarnert
Commented Jun 11, 2013 at 21:07

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