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I need to automate a process using a script and generate output files similar to the name of the input files but with some additions to it.

my process is a Java code. two input arguments and two output arguments.

java #process_class# abc.txt abd.txt abc.1.out abd.a.out

If i want to iterate this for the set of text files in my folder how can i do this

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2 Answers 2

up vote 1 down vote accepted

If you have the files a.txt, b.txt, and c.txt in the directory in which this is run, this program will output a_2.txt, b_2.txt, and c_2.txt with foo appended to each (replace the foo line with your processing commands).

for f in *.txt;
    do f2=${f%.*}_2.txt;
    cp $f $f2;
    echo "Processing $f2 file...";
    echo "foo" >> $f2; # Your processing command here
done
share|improve this answer
    
thank you sir. my process is a Java code. two input arguments and two output arguments. java <process> abc.txt abd.txt abc.1.out abc.a.out If i want to iterate this for the set of text files in my folder how can i do this – Vignesh Jun 13 '13 at 20:16
    
Can you clarify what you mean so I can help you out? Do you want to run the java process on every file in the directory? Can you type out a few of the iterations? – 22222222 Jun 13 '13 at 20:26
    
yea. My folder has twenty text files. a1,a2 to a10 and b1,b2 to b10. my java program takes each of a files and b files and generates output. Iter1: input: a1.txt, b1.txt output: a1.processed.1.txt, b1.processed.1.txt Iter2: Input a2.txt, b2.txt Output: a2.processed.2.txt, b2.processed.2.txt This has to go on for all twenty files, that is ten iterations. This is given to a java program as java #program# a1.txt b1.txt a1.processed.1.txt b1.processed.1.txt. Instead of running this java script individually, i am iterating it using a script. (contd;) – Vignesh Jun 13 '13 at 20:34
    
for entry in ls a*.txt;do for extry1 ls b*.txt;do java #process# $entry $entry1 <automated output file names> <automated output file names> done done In the place of <>s i need to automate the file names – Vignesh Jun 13 '13 at 20:35
    
for num in $(seq 1 10); do java program a$num.txt b$num.txt a$num.processed.$num.txt b$num.processed.$num.txt; done; – 22222222 Jun 13 '13 at 20:42
up vote 0 down vote 
VAR="INPUTFILENAME"
# One solution this does not use the VAR:
touch INPUTFILENAME{1,2,3,4,5,6,7,8,9,10}
# Another
for i in `seq 1 20` ; do
  touch "${VAR}${i}"
done

And there are several other ways.

share|improve this answer
    
thank you sir. my process is a Java code. two input arguments and two output arguments. java <process> abc.txt abd.txt abc.1.out abc.a.out If i want to iterate this for the set of text files in my folder how can i do this – Vignesh Jun 13 '13 at 20:19

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