Passing an array as a function parameter in JavaScript

Question

i'd like to call a function using an array as a parameters:

var x = [ 'p0', 'p1', 'p2' ];
call_me ( x[0], x[1], x[2] ); // i don't like it

function call_me (param0, param1, param2 ) {
    // ...
}

Is there a better way of passing the contents of x into call_me()?

Ps. I can't change the signature of call_me(), nor the way x is defined.

Thanks in advance

If you can't edit the function signature or how x is declared, then I don't really see how you could change it into anything better

KaptajnKold · Accepted Answer · 2010-05-18 10:02:30Z

up vote 36 down vote accepted

This does exactly what you want:

var x = [ 'p0', 'p1', 'p2' ];
call_me.apply(this, x);

edited May 18 '10 at 10:02

answered May 18 '10 at 9:44

KaptajnKold
1,8021430

Thanx, that's what i wanted. – Robert May 18 '10 at 11:57

plexer · Answer 2 · 2010-05-18 10:05:19Z

up vote 8 down vote

Assuming that call_me is a global function, so you don't expect this to be set.

var x = ['p0', 'p1', 'p2'];
call_me.apply(null, x);

answered May 18 '10 at 10:05

plexer
1,7531510

Karl Johan · Answer 3 · 2010-05-18 09:59:50Z

up vote 6 down vote

Why dont you pass the entire array and process it as needed inside the function?

Like so:

var x = [ 'p0', 'p1', 'p2' ]; 
call_me(x)
function call_me(params){
  for(i=0;i<params.length;i++){
    alert(params[i])
  }
}

answered May 18 '10 at 9:59

Karl Johan
1,697820

6

It's because i can't modify call_me(). It is defined in some other library and it is not possible to mess with the API. – Robert May 18 '10 at 11:54

3 Answers