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up vote -2 down vote favorite

Is there any way to pass string variable to array() function:

$ints = '112233,112234';
$arr = array($ints);

//instead of

$arr = array(112233,112234);

I know that there are plenty other ways, but passing the string is my only option:

$stArr = array();
foreach($dataTeacherAssWr[0]->getStudents() as $student) {
    $stArr[] = $student->getIdUser();
}
MyCacheManager::clearAssignmentCacheOnHomepageForUsers($_SESSION['id_user'], $stArr);

and the method:

public static function clearAssignmentCacheOnHomepageForUsers($teacherId, $studentId) {
    return self::clearAssignmentCacheOnHomepage(
        Array(
            'teacherIds' => array($teacherId),
            'studentIds' => array($studentId)
        )
    );
}

as you can see I can pass $studentId as "flat" ids in string

share|improve this question
2  
array() is a language construct not a function, and you might misinterpret it's usage if you look at it as a function. –  Yoshi Nov 16 '12 at 9:34
1  
You need to be clearer as to why you think passing a string into array() is your only option, and what you hope to achieve. –  Paul Gregory Nov 16 '12 at 10:17
    
$stArr = array(); foreach($dataTeacherAssWr[0]->getStudents() as $student) { $stArr[] = $student->getIdUser(); } MyCacheManager::clearAssignmentCacheOnHomepageForUsers($_SESSION['id_user'], $stArr); public static function clearAssignmentCacheOnHomepageForUsers($teacherId, $studentId) { return self::clearAssignmentCacheOnHomepage( Array( 'teacherIds' => array($teacherId), 'studentIds' => array($studentId) ) ); } –  Wojciechk Nov 16 '12 at 13:29
    
I guess $teacherId and $studentId are strings formatted like "112233,112234" ? Literally all you need to do is replace 'teacherIds' => array($teacherId); with 'teacherIds' => explode(',',$teacherId); and the same for 'studentIds' => ... ... so you don't have to use array(); –  Maccath Nov 16 '12 at 16:39
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4 Answers

up vote 2 down vote

You could use explode()

$array = explode(",", $string);

Input: 

$string = '112233,112234';
$array = explode(",", $string);
var_dump($array);

Output:

array(2) { [0]=> string(6) "112233" [1]=> string(6) "112234" }
share|improve this answer
    
please, read the question! language construct array() is my only option –  Wojciechk Nov 16 '12 at 10:10
1  
@Wojciechk That isn't possible. Array will take a comma separated list, won't take a string and separate it out for you. –  DarkCthulhu Nov 16 '12 at 10:12
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up vote 2 down vote

Try using the explode function to split the numbers separated by commas into an array...

explode(',', $ints);

With your example...

$ints = '112233,112234';
$arr = explode(',', $ints);

Produces the following output:

Array ( [0] => 112233 [1] => 112234 )

If you are looking to pass a string to the language construct array(), it simply cannot be done. You can give it a comma separated list for example array(112233, 112234); but you cannot give it array("112233,112234"); The array() documentation will explain what syntax it will accept.

It will not know that the comma separates a list of integers and that you want it split. All it cares is that you've given it a string, so it will create an array with a string in it. It's not a mind-reader, so you need to separate the values yourself.

share|improve this answer
1  
doc: php.net/manual/en/function.explode.php –  Jan Dvorak Nov 16 '12 at 9:33
    
as I mentioned - I need to pass the string to language construct –  Wojciechk Nov 16 '12 at 10:09
1  
Why do you need to? You can't pass a string to the language construct. Check the docs for the syntax it will accept: uk1.php.net/manual/en/function.array.php . What exactly is stopping you from using explode instead? It produces exactly the same response. –  Maccath Nov 16 '12 at 10:12
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up vote 1 down vote

If you must have your data in a comma-separated string, you can simply explode it on the comma to get the array:

$ints = '112233,112234';
$arr = explode(',', $ints);
share|improve this answer
    
please, read the question! language construct array() is my only option –  Wojciechk Nov 16 '12 at 10:10
1  
@Wojciechk language construct array() has a specific syntax. You cannot require to use one construct with a syntax from another. If you cannot use explode but do require a CSV string, then you simply cannot achieve what you're after. –  Aleks G Nov 16 '12 at 10:13
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up vote 1 down vote

This is another way:

    $separator=",";
    $str="112233,112234,112235,112236,112237";
    $arr = explode($separator, $str);
    //print_r($arr);
share|improve this answer
    
Please consider upvoting existing, correct answers instead of posting your own, similar one that doesn't seem to bring anything new to the table. =) –  J. Steen Nov 16 '12 at 13:40
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