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up vote 0 down vote favorite

Can anyone help with a little code i want to make array which first index will have first word of textbox text:

array[0] first word of text array[1] second word of text

can anyone help me?

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6  
Have you tried anything on this? I could write the function for you, but I don't think that would really help you. Help us help you! – Tim Jul 12 '13 at 14:40
up vote 3 down vote 
string str = "Hello Word Hello" ;
var strarray = str.Split(' ') ;

You can replace the str with TextBox.Text...

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thanks guys now how i can see result on label? i mean i have 2 labels and i want to make next: on first label text i want to type first word on second label second word – user2576809 Jul 12 '13 at 15:09
up vote 2 down vote

Use the Split method of the string type.

It will split your string by a character specification to a string array (string[]).

For example:

textBox1.Text = "The world is full of fools";
string[] words = textBox1.Text.Split(' ');
foreach(string word in words)
{
  //iterate your words here
}
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1  
Did you downvote him for using the same variable names in a one-liner piece of throwaway example code?? – Tim Jul 12 '13 at 14:46
    
@SirajMansour No one has ownership of any code and I can't see that you wrote my code. – Yair Nevet Jul 12 '13 at 14:50
up vote 1 down vote

If they are seperated by spaces :

var MyArray = MyTextBox.Text.Split(' ');
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up vote 0 down vote

There's a very simple way of doing this:

string text = "some text sample";
List<string> ltext = text.Split(' ').ToList();
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up vote 0 down vote

U can use the split method,it gets a string array back,you need to pass a char array with the characters to split upon:

string[] str = textBox1.Text.Split(new char[] { ' ', ',', ':', ';', '.' });
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up vote 0 down vote

use .Split() method like this:

var array = textboxText.Split(' ');
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He asked for an array :) – Siraj Mansour Jul 12 '13 at 14:43
    
@Alexy the split function returns a string[] no need for the .ToArray() in the end – Siraj Mansour Jul 12 '13 at 14:50
    
and no need for var either :) --best practices:if you know you need an int just declare an int as if you know you need(or that you will get and string[])just declare string[]. – terrybozzio Jul 12 '13 at 14:59
1  
@SirajMansour I agree with you – Oleksii Aza Jul 12 '13 at 15:08

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