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I want to pass array myWorkout to 'play_workout.php'. I want 'play_workout.php' to open and display the contents of myWorkout (for this example). (Once I see that this is working I will parse the data from myWorkout and write it back to a database). I'm not getting any errors in firebug, but play_workout is not being opened nor is is capturing the array object myWorkout.

I would appreciate a second glance at this. Thanks as always!

page workout_now.php

<div id="playworkout"><button onClick="playWorkout()">Play Workout</button></div>

JAVASCRIPT

function playWorkout(){

  var arr = $("#dropTargetframe > li").map(function(){
  return $(this).attr('data-id');}).get();

     var myRoutine = arr;
     var myWorkout = new Array();
        for (var i in myRoutine){
           if (myRoutine[i])
             myWorkout.push(myRoutine[i]);
            }
          //array appears like ["4", "5", "1", "4"]
          JSON.stringify(myWorkout);
          encodeURIComponent(myWorkout);

         var url = "http://localhost/RealCardio/play_workout.php";

         $.get(url, myWorkout);

page play_workout.php

<?php
 ...
 $arrayWorkout = json_decode($_REQUEST['myWorkout']); 
 print_r($arrayWorkout);     
...
?>
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3  
exact duplicate stackoverflow.com/questions/891320/… – samccone Mar 6 '12 at 22:17

4 Answers

up vote 1 down vote accepted

Assuming, that as in your comment the array elements doesn't contain any special chars, just numbers, simply do 

var myWorkoutPost=myWorkout.join('x');

Transport this to the server the way you want (form hidden field, AJAX, ..) and in PHP do

$myWorkout=explode('x',$_REQUEST['myWorkoutPost']);
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What would I populate in .join(x)? What value goes in 'x'? – Derek Mar 9 '12 at 3:13
Sorry, was a typo, should have been 'x' , not x , I have edited my answer. – Eugen Rieck Mar 9 '12 at 9:12
up vote 1 down vote

Both PHP and Javascript use JSON encoding so I would say the best way would be to JSON encode the array and then POST it as a hidden field to the PHP page and use JSON decode.

http://www.php.net/manual/en/function.json-decode.php

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up vote 0 down vote

Encode this array to JSON, send it to php script and recieve it with $_POST. Finally, decode JSON in php script.

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up vote 0 down vote

A work flow for almost every structured values 99% of the time it will do.

  • Use JSON.stringify([1,2,3]) it will give you a string "[1,2,3]".
  • Encode it with encodeURIComponent("[1,2,3]") you'll have something like this "%5B1%2C2%2C3%5D"
  • Now it's save to be sent to PHP or any other server side language try to use XMLHttpRequest or better jQuery.get() to send the values to PHP.

In php you'd do this: - $arrayOfValues = json_decode($_REQUEST['name_of_parameter']); - print_r($arrayOfValues);

Normally you'd need to include JSON library to support old browsers. More info on JSON.

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Is this how I would pass it in javascript - $.get('play_workout.php',myWorkout,'','json'); – Derek Mar 7 '12 at 13:53
I revised the question a little. Can you take another look? – Derek Mar 8 '12 at 18:45

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